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RSB [31]
3 years ago
13

What is the maximum number of electrons in p&q shell​

Chemistry
2 answers:
Bad White [126]3 years ago
5 0

Answer:

6 electrons

Explanation:

:)

hope this helps :))))))))

Aleonysh [2.5K]3 years ago
4 0

Answer:

each p shell can hold max. 6 electorns

i dont know what a q shell is

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What is the relationship between temperature and volume?
Lelu [443]

Answer:

Charles's law states that the volume of a given amount of gas is directly proportional to its temperature on the kelvin scale when the pressure is held constant

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law)

Explanation:

~Hope this helps

6 0
3 years ago
5.6 g of Iron reacts with excess fluorine gas.
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Explanation: 5.6 g = 1/10 mole Fe

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3 years ago
High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to purify chemical substances. The pre
Viktor [21]
Its running pressure in torr would be :

5.10 x 10^8 pa  x 1kPa/1000 Pa x 760 / 101.325 kPa

= 5.10 x 10 ^5  x   76 x 10^-1  x 1.01325 x 10 ^-2

= 392.7375 x 10^2

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ope this helps
5 0
4 years ago
Read 2 more answers
As altitude increases air pressure decreases <br><br> true or false
dem82 [27]
True. Pressure decreases with increasing altitude. 
8 0
3 years ago
If the pressure on the surface of water in the liquid stato
Novosadov [1.4K]

The water will boil at C) 80°C

<h3>Further explanation</h3>

Given

Vapour pressure of water = 47 kPa

Required

Boiling point of water

Solution

We can use the Clausius-Clapeyron equation :

\tt ln(\dfrac{P_1}{P_2})=\dfrac{-\Delta H_{vap}}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})

Vapour pressure of water at boiling point 100°C=101.325 kPa

ΔH vap for water at 100°C=40657 J/mol

R = 8.314 J/mol K

T₁=boiling point of water at 101.325 kPa = 100+273=373 K

Input given values :

\tt ln\dfrac{101.325}{47}=\dfrac{-40657}{8.314}(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.7682=4890.1852(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\0.0001571=(\dfrac{1}{373}-\dfrac{1}{T_2})\\\\\dfrac{1}{T_2}=0.00283\rightarrow T_2=353~K=80^oC

6 0
3 years ago
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