1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arlecino [84]
4 years ago
10

High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to purify chemical substances. The pre

ssures used in this procedure range from around 500 kilopascals (500,000 Pa) to about 60,000kPa (60,000,000Pa ). It is often convenient to know the pressure in torr. If an HPLC procedure is running at a pressure of 5.10×10^8 , what is its running pressure in torr?
Chemistry
2 answers:
Bezzdna [24]4 years ago
6 0

Answer:

3.83x10^6torr

Explanation:

Hello,

In this case, to perform the following unit conversion, it is convenient to know that 1 atm equals 101,325 Pa and 1 atm equals 760 torr:

5.10x10^8Pa*\frac{1atm}{101325Pa}*\frac{760torr}{1atm}=3.83x10^6torr

Best regards.

Viktor [21]4 years ago
5 0
Its running pressure in torr would be :

5.10 x 10^8 pa  x 1kPa/1000 Pa x 760 / 101.325 kPa

= 5.10 x 10 ^5  x   76 x 10^-1  x 1.01325 x 10 ^-2

= 392.7375 x 10^2

= 3.927275 x 10^4

ope this helps
You might be interested in
Match the term (Endothermic) with the correct definition
Darya [45]

Answer:

energy goes into the chemical and cool downs the surrounding area.

5 0
3 years ago
You are asked to identify compound X (a white, crystalline solid), which was extracted from a plant seized by customs inspectors
igor_vitrenko [27]

Answer:

C2H2O4

Explanation:

To get the molecular formula, we first get the empirical formula. This can be done by dividing the percentage compositions by the atomic masses. The percentage compositions are shown as follows :

C = 26.86%

H = 2.239%

O = 100 - ( 26.86 + 2.239) = 70.901%

We then proceed to divide by their atomic masses. Atomic mass of carbon is 12 a.m.u , H = 1 a.m.u , O = 16 a.m.u

The division is as follows:

C = 26.86/12 = 2.2383

H = 2.239/1 = 2.239

O = 70.901/16 = 4.4313

We now divide each by the smallest number I.e 2.2383

C = 2.2383/2.2383 = 1

H = 2.239/2.2383 = 1

O = 4.4313/2.2383 = 1.98 = 2

Thus, the empirical formula is CHO2.

To get the molecular formula, we use the molar mass .

(CHO2)n = 90

We add the atomic masses multiplied by n.

(12 + 1 + 2(16))n = 90

45n = 90

n = 90/45 = 2.

Thus , the molecular formula is C2H2O4

4 0
3 years ago
Complete combustion of 7.40 g of a hydrocarbon produced 22.4 g of CO2 and 11.5 g of H2O. What is the empirical formula for the h
cluponka [151]
<span>C2H5 First, you need to figure out the relative ratios of moles of carbon and hydrogen. You do this by first looking up the atomic weight of carbon, hydrogen, and oxygen. Then you use those atomic weights to calculate the molar masses of H2O and CO2. Carbon = 12.0107 Hydrogen = 1.00794 Oxygen = 15.999 Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 Molar mass of CO2 = 12.0107 + 2 * 15.999 = 44.0087 Now using the calculated molar masses, determine how many moles of each product was generated. You do this by dividing the given mass by the molar mass. moles H2O = 11.5 g / 18.01488 g/mole = 0.638361 moles moles CO2 = 22.4 g / 44.0087 g/mole = 0.50899 moles The number of moles of carbon is the same as the number of moles of CO2 since there's just 1 carbon atom per CO2 molecule. Since there's 2 hydrogen atoms per molecule of H2O, you need to multiply the number of moles of H2O by 2 to get the number of moles of hydrogen. moles C = 0.50899 moles H = 0.638361 * 2 = 1.276722 We can double check our math by multiplying the calculated number of moles of carbon and hydrogen by their respective atomic weights and see if we get the original mass of the hydrocarbon. total mass = 0.50899 * 12.0107 + 1.276722 * 1.00794 = 7.400185 7.400185 is more than close enough to 7.40 given rounding errors, so the double check worked. Now to find the empirical formula we need to find a ratio of small integers that comes close to the ratio of moles of carbon and hydrogen. 0.50899 / 1.276722 = 0.398669 0.398669 is extremely close to 4/10, so let's reduce that ratio by dividing both top and bottom by 2 giving 2/5. Since the number of moles of carbon was on top, that ratio implies that the empirical formula for this unknown hydrocarbon is C2H5</span>
3 0
3 years ago
What causes this nuclear reaction to occur
IrinaVladis [17]

Answer:

bombarding it with an energetic particle

Explanation:  nuclear reaction, a change in the identity or characteristics of an atomic nucleus, induced by bombarding it with an energetic particle. The bombarding particle may be an alpha particle, a gamma-ray photon, a neutron, a proton, or a heavy-ion.

8 0
2 years ago
Which of the following could be a long-term health effect of chemical pesticide use?
Helen [10]
The correct Answer for this question is D
3 0
3 years ago
Other questions:
  • A solution of ammonium carbonate is mixed with a solution of magnesium nitrate. If magnesium carbonate is insoluble in water, wh
    11·1 answer
  • Sodium hydroxide is a substance that causes severe burns. It is used in many educational laboratory activities but, because of i
    6·1 answer
  • Three of the primary components of air are
    11·1 answer
  • Compare table salt and glucose
    10·1 answer
  • The _____ law of thermodynamics states that the tendency of the universe is to increase entropy.
    8·2 answers
  • Which is the most important characteristic in determining an elements chemical properties
    14·1 answer
  • What do you call the ability of a gas to completely spread out and mix with other substances?
    7·2 answers
  • What would be the voltage (Ecell) of a voltaic cell comprised of Cr (s)/Cr3+(aq) and Fe (s)/Fe2+(aq) if the concentrations of th
    14·1 answer
  • For the skeletal chemical equation
    11·1 answer
  • A voltaic cell consists of an Mn/Mn2 half-cell and a Pb/Pb2 half-cell. Calculate [Pb2 ] when [Mn2 ] is 1.1 M and E cell is 0.44
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!