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Arlecino [84]
3 years ago
10

High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to purify chemical substances. The pre

ssures used in this procedure range from around 500 kilopascals (500,000 Pa) to about 60,000kPa (60,000,000Pa ). It is often convenient to know the pressure in torr. If an HPLC procedure is running at a pressure of 5.10×10^8 , what is its running pressure in torr?
Chemistry
2 answers:
Bezzdna [24]3 years ago
6 0

Answer:

3.83x10^6torr

Explanation:

Hello,

In this case, to perform the following unit conversion, it is convenient to know that 1 atm equals 101,325 Pa and 1 atm equals 760 torr:

5.10x10^8Pa*\frac{1atm}{101325Pa}*\frac{760torr}{1atm}=3.83x10^6torr

Best regards.

Viktor [21]3 years ago
5 0
Its running pressure in torr would be :

5.10 x 10^8 pa  x 1kPa/1000 Pa x 760 / 101.325 kPa

= 5.10 x 10 ^5  x   76 x 10^-1  x 1.01325 x 10 ^-2

= 392.7375 x 10^2

= 3.927275 x 10^4

ope this helps
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Phenolphthalein is a chemical compound with the formula C20H14O4 and is often written as "HIn" or "phph" in shorthand notation. Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.

3 0
2 years ago
Read 2 more answers
PLEASE HELP ME
ki77a [65]

Answer:

1.15 atm

Explanation:

According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.

Therefore we have:

Total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

We were given the following:

Total pressure = 2.45 atm

Pressure of oxygen = 0.65 atm

Pressure of carbon monoxide = x

Pressure of carbon dioxide = 0.65 atm

Therefore:

2.45 = x + 0.65 + 0.65

2.45 = x + 1.3

x = 2.45 - 1.3

x = 1.15 atm

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3 years ago
How strong are bonds between subatomic particles?
Aleks [24]

Answer:

they are indeed very strong

8 0
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A compound's properties are different than the properties of the elements that make it up.
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The answer is True because elements in a compound combine and become an entirely different substance with its own unique properties.
7 0
3 years ago
onsider the reversible dissolution of lead(II) chloride. P b C l 2 ( s ) − ⇀ ↽ − P b 2 + ( a q ) + 2 C l − ( a q ) PbClX2(s)↽−−⇀
Sveta_85 [38]

Answer:

9.34x10^-4

Explanation:

Step 1:

The balanced equation for the reaction.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

Step 2:

Data obtained from the question:

Mass of PbCl2 = 0.2393 g

Volume = 50mL

concentration of Pb^2+, [Pb^2+] = 0.0159 M

Concentration of Cl^-, [Cl^-] = 0.0318 M

Equilibrium constant, Kc =?

Step 3:

Determination of the number of mole PbCl2.

The number of mole of PbCl2 can be obtained as follow:

Molar Mass of PbCl2 = 207 + (35.5x2) = 278g/mol

Mass of PbCl2 = 0.2393 g

Number of mole =Mass /Molar Mass

Number of mole of PbCl2 = 0.2393/278 = 8.61x10^-4 mole

Step 4:

Determination of Molarity of PbCl2.

At this stage we shall obtain the molarity of PbCl2. This is shown below:

Mole of PbCl2 = 8.61x10^-4 mole

Volume = 50mL = 50/1000 = 0.05L

Molarity of PbCl2 =?

Molarity = mole /Volume

Molarity of PbCl2 = 8.61x10^-4/0.05

Molarity of PbCl2 = 0.01722 M

Step 5:

Determination of the equilibrium constant Kc.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

The equilibrium constant Kc for the equation above is given by:

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

[Pb^2+] = 0.0159 M

[Cl^-] = 0.0318 M

[PbCl2] = 0.01722 M

Kc =?

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

Kc = 0.0159 x (0.0318)^2/ 0.01722

Kc = 9.34x10^-4

5 0
3 years ago
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