Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach? well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.
if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.
the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.
Answer:
Step-by-step explanation:
So this is just playing with the pythagorean theorem
a^2 + b^2 = c^2 with a and b as legs and c as the hypotenuse.
Let's say a is equal to 1500 so then c is 4 times b
1500^2 + b^2 = (4b)^2 Now we just treat this like a normal algebraic expression
2,250,000 = 16b^2 - b^2
2,250,000 = 15b^2
150,000 = b^2
sqrt(150,000) = b
100sqrt(15) = b
You can check this now.
1500^2 + sqrt(150,000)^2 = c^2
sqrt(2,250,000 + 150,000) = c
sqrt(2,400,000) = c
400sqrt(15) = c Which fits the requirement of c = 4b
Answer:
all two digit whole number which are divisible by 11 are
22+33+44+55+66+77+88+99=484
so square root is really is easyyy put in 6.4 ♾️