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Marrrta [24]
3 years ago
10

Lulu and nana are not transgenic, but they are genetically modified. Explain the difference. Also explain how every cell in thei

r bodies ended up with the genetic modification, rather than just certain tag they tissues
Biology
1 answer:
Murrr4er [49]3 years ago
8 0

Answer: the tissue

Explanation:

Tissue is the beginning of a cell in the external human body

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The fluid that surroundeds all cells in the body is konw as. ​
BartSMP [9]

Answer:

Extracellular fluid

Explanation:

A proportion of this fluid is plasma

4 0
3 years ago
What do you notice about the ligands and their receptors in these images?
aliina [53]

Answer:

What can be noticed about the ligands and their receptor is that the configuration of both coincide, as a key would with its lock, which demonstrates the specificity of a receptor by its ligand.

Explanation:

A <u>ligand</u> corresponds to a molecule considered a signal or a messenger, while the <u>receptor</u> is a protein on the cell surface, with the capacity to accept a ligand.

Ligands and receptors constitute pairs that complement each other, so that <u>each receptor can bind to a specific ligand</u>, similar to what happens with a key and a lock.

Once the ligand-receptor complex is formed, changes occur inside the cell, which define a certain effect.

8 0
3 years ago
EXPERT HELP I'LL GIVE BRAINLIEST:
kupik [55]
You are right it’s D
Wish you luck
6 0
2 years ago
22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
3 years ago
How can you get fat from eating too many carbohydrates
lbvjy [14]
If you don't use them they get stored as glycogen, for later use. buy if you're not active, it can lead to obesity.
5 0
3 years ago
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