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zlopas [31]
4 years ago
5

N and p are integers greater than 1;

Mathematics
1 answer:
yan [13]4 years ago
5 0

Answer: 14

Step-by-step explanation:

We want the smallest value so:

we know 5n is the square of a number, so

n = 5a^2, so a > 1

we know 75np is the cube of a number, so

p= 3^2a = 9a

Now, n+p = 5a^2 + 9a = a [5a+9]

The smallest value would be when a=1

Therefore when you plug it in , n+p = 5+9 = 14

Hopefully that helped :)

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Find the slope of the line that is ​(a) parallel and ​(b) perpendicular to the line through the pair of points.
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Answer:

a) The slope of the line is parallel to the another line m=4

b) The slope of the line is perpendicular to the another line m=\frac{-1}{4}

Step-by-step explanation:

Step1:-

<u>Slope of a line</u><u> :-</u>

If θ is the inclination of a line 'l' then tanθ is called the slope or gradient of the line 'l'.The slope of a line is denoted by m=tanθ

The slope of a line given two points m=\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

<u>Parallel lines:-</u>

<u>Two </u>non-vertical lines are parallel if and only if their slopes are parallel

<u>Perpendicular lines:-</u>

<u>Two </u>non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

m_{2} = \frac{-1}{m_{1} } \\

<u>Step 2</u>:-

a)The slope of a line when given two points (-1,-4) and (0,0)

m = \frac{0-(-4)}{0-(-1)} =4

<u>Two </u>non-vertical lines are parallel if and only if their slopes are parallel

m_{1} = m_{2}

Therefore the slope of the line that is parallel to the another line

m_{1} =m_{2} =4

<u>Step 3</u>:-

b) <u>Two </u>non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

m_{2} = \frac{-1}{m_{1} } \\

m_{2} =\frac{-1}{4}

Therefore the slope of the line is perpendicular to the another line is

m=\frac{-1}{4}

3 0
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