Answer:
a. 0.28
Explanation:
Given that
porosity =30%
hydraulic gradient = 0.0014
hydraulic conductivity = 6.9 x 10⁻4 m/s
We know that average linear velocity given as
The velocity in m/d ( 1 m/s =86400 m/d)
v= 0.27 m/d
So the nearest answer is 'a'.
a. 0.28
Answer:
vertical load = 10 kN
Modulus of elasticity = 200GPa
Yield stress on the cable = 400 MPa
Safety factor = 2.0
Explanation:
Data
let L =
= 3.35 m
substituting 1.5 m for h and 3 m for the tern (a + b)
= tan⁻¹()
= 45⁰
substituting 1.5 for h and 3 m for (a+ b) yields:
₂ = tan⁻¹ ()
=25.56⁰
checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.
Answer:
The prototypical bridge is quite simple—two supports holding up a beam—yet the engineering problems that must be overcome even in this simple form are inherent in every bridge: the supports must be strong enough to hold the structure up, and the span between supports must be strong enough to carry the loads.
Explanation:
Answer:
3180.86 Nm
Explanation:
Moment of inertia for shaft AB,
Torque in solid shaft AB will be given by
Where is shear stress, is polar moment of inertia for shaft AB, r is the radius of shaft B
The inner diameter of pipe CD can found considering that the thickness of pipe is 0.006 m hence diameter= 0.09-(2*0.006)= 0.078 m
Moment of inertia for shaft CD will be
Torque for shaft CD will be
and here r = 0.045 m
The minimum of the two torques is the largest torque that can be applied. Therefore, the torque to apply equals 3180.86 Nm