Question

Series parallel circuits

Answer 1

Answer:

$I_T=2A$

Explanation:

Find the total resistance. R3, R4, R5 are in series so add them up.

They are parellel to R2 so add that up. Then that is in series with R1 so add that up.

$R_t=((R3+R4+R5)||R2)+R1$

$R_T=((2+4+2)||8)+2$

$R_T=((8)||8)+2$

$R_T=(\frac{(8)(8)}{8+8})+2$

$R_T=(4)+2$

$R_T=6\Omega$

V=IR. Rearrange the equation to solve for I (current).

$I_T=\frac{E}{R_T}$

$I_T=\frac{12}{6}$

$I_T=2A$