Answer:
D
Explanation:
ensuring project end on time through carefully planning and organizing
Answer:
v1QAZ3EDCRFV5TGB6YHNUJMIK,9OL0K9MIJNUHB7YGVTFCRDXESZWAq
Explanation:
qaAQzwsxedcnujmik,ol mkjuhtfcrxdZSWAQWSEDRFTGYHUJIKO,LP.; ,LMKJNUHTGDXESZWaEDRFTGHJKL,MNBVFDSWQAAWERTYUIOP;L,MNHGFDEWwertyuikolp;[l.,mnbvfre345678990098765434rtyhnbhju8765rtghjui875rfghji8765rfghju7654redfghu7643erfghji987yhjko987y
When a slender member is subjected to an axial compressive load, it may fail by a ... Consider a column of length, L, cross-sectional Moment of Inertia, I, having Young's Modulus, E. Both ends are pinned, meaning they can freely rotate ... p2EI L2 ... scr, is the Euler Buckling Load divided by the columns cross-sectional area
Answer:
R= 53.7 Ω
Explanation:
fc= 1/(2πRC)
3000=1/(2π× 1 × 10^-6 × R)
R= 53.7 Ω
