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zepelin [54]
3 years ago
12

40 = 6(X^2) / 4 (tan(180/6)) solve for X

Engineering
1 answer:
const2013 [10]3 years ago
3 0

Answer:

x = 3.92

Explanation:

The question is given as ;

40 = 6x² / 4 tan { 180/6}

40 = 6x² / 4 tan {30°}

40 = 6x² / 2.309

40 * 2.309 = 6x²

92.38 = 6 x²

92.38/6 = x²

15.40 = x²

√15.40 = x

x = 3.92

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The roof of a refrigerated truck compartment consists of a layer of foamed urethane insulation (t2 = 21 mm, ki = 0.026 W/m K) be
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Answer:

Tso = 28.15°C

Explanation:

given data

t2 = 21 mm

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net solar radiation into the roof = 107 W/m²

temperature of the inner surface Ts,i = -4°C

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solution

As when energy on the outer surface at roof of a refrigerated truck that is balance as

Q = \frac{T \infty - T si }{\frac{1}{hA}+\frac{t1}{AKp}+\frac{t2}{AKi}+\frac{t1}{aKp}}       .....................1

Q = \frac{T \infty - Tso}{\frac{1}{hA}}                         .....................2

now we compare both equation 1 and 2 and put here value

\frac{29-(-4)}{\frac{1}{47}+\frac{2\times0.009}{180}+\frac{0.021}{0.026}} = \frac{29-Tso}{\frac{1}{47}}            

solve it and we get

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Answer:

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Explanation:

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