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tatuchka [14]
3 years ago
11

Determine whether or not each of the following signals is periodic.

Engineering
1 answer:
Sloan [31]3 years ago
3 0

Answer:

a) periodic (N = 1)

b) not periodic

c) not periodic

d) periodic (N = 8)

e) periodic (N = 16)

Explanation:

For function to be a periodic: f(n) = f(n+N)

a) x[n]=sin(\frac{8\pi}{2}n+1)\\\\sin(\frac{8\pi}{2}n+1)=sin(4\pi n+1)

It is periodic with fundamental period N = 1

b) x[n]=cos(\frac{n}{8} -\pi)\\\\\frac{1}{8} N=2\pi k

N must be integer. So it is nor periodic

c) x[n]=cos(\frac{\pi}{8} n^2)\\\\cos(\frac{\pi}{8} (n+N)^2)=cos(\frac{\pi}{8} (n^2+N^2+2nN)\\\\N^2 = 16 \:\:or\:\:2nN=16

Since N is dependent to n. So it is not periodic.

d) x[n]=cos(\frac{\pi }{2}  n) cos(\frac{\pi }{4}  n)\\\\x[n] = \frac{1}{2} cos(\frac{3\pi }{4} n) + \frac{1}{2} cos(\frac{\pi }{4} n)\\\\N_1=8\:\:and\:\:N_2=8\\

So it is periodic with fundamental period N = 8.

e) x[n]=2cos(\frac{\pi }{4}  n)+sin(\frac{\pi }{8} n)-2cos(\frac{\pi }{2} n+\frac{\pi }{6} )\\\\N_1=8\:\:and\:\:N_2=16\:\:and\:\:N_3=4

So it is periodic with N = 16.

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