Plz help me with questions 2b

Mathematics

1 answer:

castortr0y [4]3 years ago

4 0

Solve for y, then plug in the answer for the y in the other equation

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(m 5/6) (m1/6) ^7 = m^x

nadezda [96]

Answer:

x = 2

Step-by-step explanation:

Here, we want to find the value of x

(m^5/6)(m^1/6)^7 = m^x

= (m^5/6)(m^7/6) = m^x

Using the law of indices for power multiplication

m^(5/6 + 7/6) = m^x

m^(12/6) = m^x

m^2 = m^x

we simply equate the powers in this case since the base are equal

Thus we have

x = 2

3 0

3 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$