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Vitek1552 [10]
3 years ago
13

I need help !!!!!!!!!!

Mathematics
2 answers:
Lana71 [14]3 years ago
6 0

Answer:19

Step-by-step explanation:

anastassius [24]3 years ago
3 0

Answer:

19

Step-by-step explanation:

1. r(-3) is just plugging in -3 into the r(x) function where ever we see x.

1a. r(-3)=-2(-3)^2+1=-17

2. We are left with q(-17).

2a. We plug -17 into where we x in q(x).

3. q(-17)=-(-17)+2=19

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Help me with this plz<br><br> Choose: Same Or opposite
adoni [48]
Opposite but I’m not very sure
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3 years ago
What is the alternating sum of digits
Morgarella [4.7K]

Answer:Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.

Hope this helped

6 0
3 years ago
Maddie and her friends are making s'mores over the campfire. they have a bag of 48 marshmallows, 2 packs of graham crackers cont
VladimirAG [237]

The answer would be 16 S'mores and the limiting reactant would be the grahams.


(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)


Limiting reactant would be the reactant that runs out first.


Let's take your problem into account and see what we have:

48 marshallows

32 grahams (2 x 16 per pack)

45 chocolate pieces (5 x 15 pieces per bar)


Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.

The maximum yield of marshmallows is 48.

The maximum yield of chocolate is 45.


Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.

8 0
3 years ago
Add or subtract the polynomials<br> (8x3+3x-2)+(9x2-7+3x-2x3)
crimeas [40]

Answer:

10x^3+9x^2-9

Step-by-step explanation:

8x^3+2x-2+9x^2-7+2x-2x^3 - Combine like terms

10x^3+9x^2-9

4 0
2 years ago
Read 2 more answers
What to do if quadratic equation has a negative spuare root?
alex41 [277]

If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 3+\sqrt{5}

then 3-\sqrt{5} will also be a solution.

3 0
3 years ago
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