8(4x+6y-2z)
32x+48y-16z
Hope this helps!
It’s either Option 1 or 4
Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x
Answer:
a. 24
b. 2
c. 0.0833 = 8.33%
Step-by-step explanation:
a.
The first "slot" of person to arrive has 4 possibilities, then the second "slot" will have 3 possibilities, as one has already arrived, then the third "slot" has 2 possibilities, and the fourth "slot" has just 1 possibility.
So, multiplying all these combinations, we have 4*3*2*1 = 24 possible ways they can arrive
b.
If the first and the last person are already "locked", we just have possibilities for the second and third person. The second will have 2 possibilities (Sergio or Tyrone), and the third will have only 1 (the person that wasn't the second between Sergio and Tyrone). So, the number of possibilities is 2*1 = 2
c.
If we have 2 cases where Dawn is first and Jim is last, from a total of 24 possible cases, the probability is 2/24 = 1/12 = 0.0833 = 8.33%
