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noname [10]
3 years ago
7

Help me with #22 please.

Mathematics
2 answers:
gogolik [260]3 years ago
7 0
Write out the Eq. for slope:
m= \frac{( y_{2} - y_{1} )}{( x_{2} - x_{1})}

(-4,8) = (x1,y1)
(r, 12) = (x2,y2)
m=\frac{4}{3}

Use this information to plug into the slope equation:
m= \frac{( y_{2} - y_{1} )}{( x_{2} - x_{1})}
\frac{4}{3} = \frac{( 12 - 8 )}{( r - (-4))}
\frac{4}{3} = \frac{( 4 )}{( r - (-4))}



Since we want the bottom of the fraction =3 set r-(-4)=3 and solve
r-(-4)=3
r+4-4=3-4
r= -1





professor190 [17]3 years ago
5 0
4/3 = (12 - 8) / (r+4)
4/3r + 16/3 = 4
4r + 16 = 12
4r = -4
r = -1

answer
G. -1
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4 years ago
What is the simplified form of the expression? 7r - 8r + 13 -2r + 5? Please help me
ArbitrLikvidat [17]

Answer:

- 3r + 18

Step-by-step explanation:

7r - 8r - 2r + 13 + 5 = 7r - 10r + 18

6 0
3 years ago
Hello! I need some help figuring out the following parts of trigonometry. Since this is a rather difficult math term to understa
Zina [86]
Alright so these ratios have many different forms but the way I use to remember the trigonometric ratios is:
SOH
CAH
TOA

This means:
Sine --> Opposite/Hypotenuse
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With that in mind, number 1:
Would be Sine, or C.

Number 2 would be, Cosine, or E.

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4 0
3 years ago
Read 2 more answers
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

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3 years ago
If KLM = STU which of the following can you NOT conclude as being true?
RoseWind [281]
The answer is C. for sure
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