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3 years ago

14

Someone plz help because I am using my last amount of points and I don't want it to be wasted from no answer.I need help with qu

estions 33,34,and 35.Help Fast will give Brainliest Answer.

1 answer:

ser-zykov [4K]3 years ago

7 0

Wheres the questions???

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What is 1 inch to 6 feet

docker41 [41]

Answer:

6 feet 1 inches in cm =

185.42 cm

7 0

3 years ago

Read 2 more answers

A flashlight has 7 batteries, 5 of which are defective. If 5 are selected at random without replacement, find the probability th

TEA [102]

71.4 % chance I think is your answer.

8 0

3 years ago

In which direction must the graph of Rx) = 7% be shifted to produce the graph of g(x) = 7% + 7?

joja [24]

Answer:

B. Up

Step-by-step explanation:

If you alter a function by adding or subtracting a constant to the end of the expression, then the graph will slide up (down if subtracting) If you alter the x value by altering the expression in close to the x with addition or subtraction the graph will slide left or right.

Vertical translations (sliding up or down) go up when adding and down when subtracting as you would expect it to.

Horizontal translations are the oppoof what you might expect. A (x-h) will shift the graph right, while a (x+k) will shift the graph left.

The answer to your question is UP.

5 0

2 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

3 years ago

Add -4 + 2/3<br><br>A) -5 2/3<br><br>B) -4 2/3<br><br>C) -3 2/3<br><br>D) -3 1/3

kodGreya [7K]

Answer:

D

Step-by-step explanation:

4 0

3 years ago