There will be no recombinant progeny in absolute linkage. The F1 inherted banded and yellow alleles (BBCY) together on one chromosome from the banded yellow parent and unbanded and brown allels (BOCBw) together on the homologous chromosome from the unbanded parent. All the F1 gametes will contain only these two allelic combinations, in equal proportions if there is no recombination. F2 cross progeny will have 1/2 banded, that is yellow and 1/2 unbanded brown.
Answer:
The phenomenon of unequal separation in meiosis is called nondisjunction. If nondisjunction causes a missing chromosome in a haploid gamete, the diploid zygote it forms with another gamete will contain only one copy of that chromosome from the other parent, a condition known as monosomy. I think sorry if wrong ;)
Your right J is sexual reproduction, and K is asexual reproduction. But sexual reproduction requires the presences of a male and a female. But other asexual reproduction doesn't, and just requires sexual maturity. They produce offspring in the form of spores for example.
Answer:
the spring time is when they call for mates
False
reason -
Gene testing is not full proof as there are possibilities of discrepancies in it based on the testing procedures used and the condition of sample. Since we human beings have the same genomic structure there are chances that our DNA may match with other people who do not share a heredity with our family. Basically statistical probability is used to determine probability of paternity, relationship of any kind etc. among two individuals . usually A 99% or higher percentage of probability is considered conclusive. and thus it gene testing can not be considered as full proof
