Question

6: A body throws a ball vertically up. It returns to the ground after 5 seconds. Find the velocity with which the ball is thrown up

Answer 1

Answer:

Explanation:

Ball rises and falls in equal periods. Because it goes by same speeds and same route. Therefore t_{rise} = t_{fall} =2.5 s

In free fall and vertical throw movement: x= (1/2).a.t^{2}

Here, we can find the height of the ball

x= (1/2).5.(2.5^{2}) = 15.625 m

From the attaches V-t graphics, x=V.t/2

15.624=V.(2.5)/2

V=12.5 m/s