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pickupchik [31]
4 years ago
8

A pendulum of length =1.0 m is pulled to the side and released on the moon. It's period is measured to be 4.82 seconds. What is

the gravity on the moon?
Physics
2 answers:
Shkiper50 [21]4 years ago
7 0

Answer:

Gravity on the moon, g = 1.69 m/s²

Explanation:

It is given that,

Length of pendulum, l = 1 m

Time period, T = 4.82 seconds

We have to find the gravity of the moon. The time period of the pendulum is given by :

T=2\pi\sqrt{\dfrac{l}{g}}

g = acceleration due to gravity on moon

g=\dfrac{4\pi^2l}{T^2}

g=\dfrac{4\pi^2\times 1\ m}{(4.82\ s)^2}

g = 1.69 m/s²

Hence, the gravity on the moon is 1.69 m/s².

skelet666 [1.2K]4 years ago
6 0

Answer:

Gravity on the moon, g = 1.69 m/s²

Explanation:

If the pendulum of length is 1.0 m is pulled to the side and released on the moon and It's period is measured to be 4.82 seconds, the gravity on the moon is 1.69 m/s².

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You have an electrically neutral toy that you divide into two pieces. You notice that at least one of those pieces has an electr
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Answer:

Attract

Explanation:

According to the properties of charge, the bodies having unlike charges attract each other and the bodies having like charges repel each other.

As the toy is initially electrically neutral, so as it is divided into two pieces, then according to the conservation of charge, the one piece having positive charge and the other piece having negative charge. As they are unlike charges so they attract each other.

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4 years ago
The free-fall acceleration on Mars is 3.7 m/s2.
hichkok12 [17]

Answer:

(a) The length of the pendulum on Earth is 36.8cm

(b) The length of the pendulum on Mars is 13.5cm

(c) Mass suspended from the spring on Earth is 0.37kg

(d) Mass suspended from the spring on Mars is 0.36kg

Explanation:

Period = 1.2s, free fall acceleration on Earth = 9.8m/s^2, free fall acceleration on Mars = 3.7m/s^2

( a) Length of pendulum on Earth = [( period ÷ 2π)^2] × acceleration = (1.2 ÷ 2×3.142)^2 × 9.8 = 0.0365×9.8 = 0.358m = 35.8cm

(b) Length of the pendulum on Mars = (1.2÷2×3.142)^2 × 3.7 = 0.0365×3.7 = 0.135cm = 13.5m

(c) Mass suspended from the spring on Earth = (force constant×length in meter) ÷ acceleration = (10×0.358) ÷ 9.8 = 0.37kg

(d) Mass suspended from the spring on Mars = (10×0.135)÷3.7 = 0.36kg

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3 years ago
Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artifici
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Answer:

Hi myself Shrushtee.

Explanation:

Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artificial gravity, human growth is stunted and biological functions break down. An effective way to create artificial gravity is through the use of a rotating enclosed cylinder, as shown in the figure. Humans walk on the inside edge of the cylinder, which is sufficiently large (diameter of 2235 meters) that its curvature is not readably noticeable to the inhabitants. (The space station in the figure is not drawn to the scale of the human.) Once the space station is rotating at the necessary speed, how many minutes would it take the space station to make one revolution?

The distance traveled by the man in one revolution is simply the circumference of the space station, C = 2p R. From this result, you should be able to deduce the time it takes for the space station to sweep out a complete revolution.

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3 years ago
Electromagnetic waves are classified into forms such as radio waves, microwaves, and infrared waves, based on the amount of ener
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Answer: D) wavelength

Explanation:

The energy E of an electromagnetc wave is given by the following formula:  

E=h.f (1)

Where:  

h is the Planck constant  

f is the frequency  

Now, the frequency has an inverse relation with the wavelength \lambda:  

f=\frac{c}{\lambda} (2)  

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Substituting (2) in (1) we have:

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This means the amount of energy an electromagnetic wave carries depends on its wavelength (or its frequency), because the speed of light and h are constant.

6 0
3 years ago
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Answer:

It was safe to handle the circuit with dry hands because dry skin body resistance is very high, measuring up to 500,000 ohms.

Explanation:

Given;

Current of 0.001 A to be felt

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Current of 0.015 A can cause a loss of muscle control

Total current that traveled in the three-battery circuit = 0.03 A

Thus, we can conclude that, it was safe to handle the above mentioned circuit with dry hands because dry skin body resistance is very high, measuring up to 500,000 ohms.

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