Find the volume of the largest right circular cone that can be inscribed in a sphere of radius 8?

What's the 2-step rules input 5,9,7,10 output 16 28 22 31

snow_tiger [21]

To solve this problem, we have to figure out a rule for the function. We are told that it is a two-step rule, so it is most likely the input multiplied by a coefficient plus a constant. Let’s let the input be represented by the variable x and the output be represented by the variable y. Using our knowledge, we can see that the outputs are close to triple the input, so we set up the preliminary equation:

y = 3x + b,

where b is a constant. If we want to solve for b, we must plug in one of our input/output pairs. If we plug in (5,16), we get the following:

16 = 3(5) + b

16 = 15 + b

1 = b

Then, we should substitute in this value into our equation and check our work.

y = 3x + 1

If we plug in the other points, this equation yields a true statement, so we know it is correct.

Hope this helps!

6 0

3 years ago

To

choli [55]

Answer: B.x^3+4x^2-19x+14 is correct

Step-by-step explanation:

(x + 7)(x2 – 3x + 2)

Multiplying both

x^3-3x^2+2x+7x^2-21x+14

x^3+4x^2-19x+14

7 0

3 years ago

Area-i need help with both

kondaur [170]

The last one + has an times eight

6 0

3 years ago

Read 2 more answers

A surveyor wishes to lay out a square region with each side having length L. However, because of measurement error, he instead l

RoseWind [281]

Step-by-step explanation:

Area, A = Length,x × Breadth,y

A=xy

When x and y are independent, E(xy) = E(x)E(y)

As x and y have the same distribution, U[L-A,L+A], they have the same mean.

We could argue by symmetry that E(x) = L and E(y) + L, also.

We can also reason this from the fact that, if X ~ U[L-A, L+A], f(x) = 1/(2A) from L-A to L+A

Therefore

$E(x)= \int\limits {f(x)} \, dx \\\\=\int\limits^{(L+A)}_{(L-A)} {\frac{1}{2A}x } \, dx$

$=\int\limits^{(L+A)}_{(L-A)} {\frac{1}{2A}x } \, dx \\\\=[\frac{1}{4A}x^2 ]\limits^{(L+A)}_{(L-A)}$

=1/(4A)(L+A)2 - 1/(4A)(L-A)2

= 1/(4A)(L2 + 2AL + A2) - 1/(4A)(L2 - 2AL + A2)

=1/(4A)(2AL+2AL)

= 1/(4A)(4AL)

= L

Thus, E(xy) = E(x)E(y) = L×L = L²

4 0

3 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8? Quadratic formula: x =Star

zlopas [31]

Answer:

1.39

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Given equation = 0=2x2+3x-8

Here, we use general formula of quadratic equation, then

$x = \frac{-b+-\sqrt{b^{2} - 4ac} }{2a}$

By taking the value by given equation,

a = 2, b = 3, c= -8

by putting the value in equation , we get

x = [- 3 ± √3^2 - 4(2 × -8)] ÷ 2×2

= [- 3 ± √73] ÷ 4

= [- 3 ± 8.544] ÷ 4

So, for positive solution, we get

x = (-3 + 8.544) ÷ 4

x = 1.386 or 1.39

3 0

3 years ago