Answer:
The statement is false.
Step-by-step explanation:
A parallelogram is a figure of four sides, such that opposite sides are parallel
A rectangle is a four-sided figure such that all internal angles are 90°
Here, the statement is:
"A rectangle is sometimes a parallelogram but a parallelogram is always a
rectangle."
Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.
The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.
The correct statement would be:
"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"
The answer is C (-1,-4)
I got the answer by graphing the equation and plotting each the points down to see which one lies on the graph
Answer:
you're question is complicated
Step-by-step explanation:
Come on now, check your book on the "product to sum" identities
![\bf cos({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[sin({{ \alpha}}+{{ \beta}})\quad -\quad sin({{ \alpha}}-{{ \beta}})]](https://tex.z-dn.net/?f=%5Cbf%20cos%28%7B%7B%20%5Calpha%7D%7D%29sin%28%7B%7B%20%5Cbeta%7D%7D%29%3D%5Ccfrac%7B1%7D%7B2%7D%5Bsin%28%7B%7B%20%5Calpha%7D%7D%2B%7B%7B%20%5Cbeta%7D%7D%29%5Cquad%20-%5Cquad%20sin%28%7B%7B%20%5Calpha%7D%7D-%7B%7B%20%5Cbeta%7D%7D%29%5D)
The height of the container be so as to minimize cost will be 1.20. inches.
<h3>How to calculate the height?</h3>
The volume of the box will be:
= 2x × 3x × h
= 6x²h
Volume = 6x²h
12 = 6x²h
h = 2x²
The cost function will be:
C = 2.60(2)(6x²) + 4.30(12x)h
C = 31.2x² + 51.6xh
Taking the derivative
62.4x + 51.6h
h = 1.20
Therefore, the height of the container be so as to minimize cost will be 1.20 inches.
Learn more about height on:
brainly.com/question/15557718
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