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inessss [21]
3 years ago
10

Which statement is true about figures ABCD and A’B’C’D’?

Mathematics
2 answers:
Brrunno [24]3 years ago
7 0

Answer:

what figures

Step-by-step explanation:

???

Marianna [84]3 years ago
4 0

Answer:

there is no figures could you please um take picture so we can help

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Amari claims that a rectangle is sometimes a parallelogram but a parallelogram is always a
Maslowich

Answer:

The statement is false.

Step-by-step explanation:

A parallelogram is a figure of four sides, such that opposite sides are parallel

A rectangle is a four-sided figure such that all internal angles are 90°

Here, the statement is:

"A rectangle is sometimes a parallelogram but a parallelogram is always a

rectangle."

Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.

The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.

The correct statement would be:

"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"

6 0
3 years ago
Graph the function y=√x+1-4. Which point lies on the graph?
nataly862011 [7]
The answer is C (-1,-4)
I got the answer by graphing the equation and plotting each the points down to see which one lies on the graph

8 0
2 years ago
Alex earn 12% Commission on any of her monthly sales over $5,000 for sales for May were $6,750 how much commission did Alex earn
Naddika [18.5K]

Answer:

you're question is complicated

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write the product cos(2x)sin(5x) as a sum
ratelena [41]
Come on now, check your book on the "product to sum" identities

\bf cos({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[sin({{ \alpha}}+{{ \beta}})\quad -\quad sin({{ \alpha}}-{{ \beta}})]
8 0
3 years ago
A container manufacturer plans to make rectangular boxes whose bottom and top measure 2x by 3x. The container must contain 12in.
lisabon 2012 [21]

The height of the container be so as to minimize cost will be 1.20. inches.

<h3>How to calculate the height?</h3>

The volume of the box will be:

= 2x × 3x × h

= 6x²h

Volume = 6x²h

12 = 6x²h

h = 2x²

The cost function will be:

C = 2.60(2)(6x²) + 4.30(12x)h

C = 31.2x² + 51.6xh

Taking the derivative

62.4x + 51.6h

h = 1.20

Therefore, the height of the container be so as to minimize cost will be 1.20 inches.

Learn more about height on:

brainly.com/question/15557718

#SPJ1

5 0
2 years ago
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