Answer:4
Step-by-step explanation:
log₂[log₂(√4x)] = 1
log₂2 =1
So we replace our 1 with log₂2
log₂[log₂(√4x)] = log₂2
log₂ on bothside will cancel each other.
We will be left with;
[log₂(√4x)] = 2
log = power of exponential
√4x = 2²
√4x = 4
Square bothside
(√4x)² = 4²
4X = 16
Divide bothside by 4
4x/4 = 16/4
x = 4
3x-5=19-x
3x-5-19+x=0
4x-24=0
4x=24
x=6
2x + 5y = 2
-3x - y =-3
-3x - y = -3
y = 3x - 3
substitute y = 3x - 3 into the first equation.
2x + 5y = 2
2x + 5(3x - 3) = 2
2x + 15x - 15 = 2
17x - 15 = 2
solve for x in 17x - 15 = 2
17x - 15 = 2
17x = 2 + 15
17x = 17
x = 1
substitute x = 1 into y = 3x - 3
y = 3x - 3
y = 3(1) - 3
y = 3 - 3
y = 0
(1, 0) << the answer
hope this helped, God bless!
