The width is11ft
hope that helps
Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
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<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.
9514 1404 393
Answer:
14.9 cm
Step-by-step explanation:
To find c using the Law of Sines, you must know angle C. That is found from ...
C = 180° -A -B = 180° -150° -12° = 18°
Then the law of sines tells you ...
c/sin(C) = b/sin(B)
c = b·sin(C)/sin(B) = (10 cm)·sin(18°)/sin(12°)
c ≈ 14.9 cm
The answer is: [B]: "arithmetic" .
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"The <u> arithmetic </u> average ignores compounding."
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