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2 years ago

a rectangle has an area of 7/8 square units if the width is 7/16 unit what is the length of the rectangle in units?

Mathematics

1 answer:

djyliett [7]2 years ago

3 0

Answer:

$Length=2 units$

Step-by-step explanation:

Given :

Area of the rectangle = $\frac{7}{8}$ square units

Width of the rectangle= $\frac{7}{16}$ units

Area of the rectangle= Length* Width

$\frac{7}{8} =Length*\frac{7}{16}$

Multiplying $\frac{16}{7}$ both the sides

$\frac{7}{8} *\frac{16}{7} =Length$

$Length=\frac{16}{8}$

$Length=2 units$

The length of the rectangle is 2 units

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Solve for x.<br> 7(1x - 3) = 4(x + 5)

alexandr1967 [171]

Answer:

x = 41/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS
Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

7(1x - 3) = 4(x + 5)

<u>Step 2: Solve for </u><em><u>x</u></em>

Simplify: 7(x - 3) = 4(x + 5)
Distribute: 7x - 21 = 4x + 20
Subtract 4x on both sides: 3x - 21 = 20
Add 21 on both sides: 3x = 41
Divide 3 on both sides: x = 41/3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

Substitute: 7(1(41/3) - 3) = 4(41/3 + 5)
Multiply: 7(41/3 - 3) = 4(41/3 + 5)
Subtract/Add: 7(32/3) = 4(56/3)
Multiply: 224/3 = 224/3

Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.

And we have our final answer!

6 0

2 years ago

Write a division problem that will have a 2 digit quotient and another division problem that will have a 3 digit quotient. Expla

o-na [289]

Answer:

$\frac{240}{4} =60$

$\frac{1800}{3} =600$

Step-by-step explanation:

1. The result should by a 2 digit number.

So, I fix a two digit number first, say 60.

Then, I multiplied it by some random integer, say 4 and got 240.

Now, 240 is my dividend and 4 is my divisor.

My division problem is:

$\frac{240}{4} =60$

2. The result should be a 3 digit number.

So, I fix a three digit number first, say 600.

Then, I multiplied it by some random integer, say 3 and got 1800.

Now, 1800 is my dividend and 3 is my divisor.

My division problem is:

$\frac{1800}{3} =600$

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3 years ago

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Need help ASAP plzzz and thank you :)

Reil [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

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Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

gizmo_the_mogwai [7]

Answer:

When y=32, x=16.5

Step-by-step explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as: $x\:\alpha \:\frac{1}{y}$

$x=\frac{k}{y}$

We have x = 132, when y=4

We can find value of k by using these values

$x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528$

We need to find x when y=32

$x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5$

So, when y=32, x=16.5

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3 years ago

HELPPPPP ME GUYSSSS........

tamaranim1 [39]

Answer:

$\rm\displaystyle (x + 2{)}^{2} + (y + 5 {)}^{2} = {1}^{}$

$\rm\displaystyle (x - 7{)}^{2} + (y + 3{)}^{2} = { 7 }$

Step-by-step explanation:

<h3>QUESTION-1:</h3>

we are given the center and the redious of a circle equation

remember that,

$\rm\displaystyle E _{c} :(x - h {)}^{2} + (y - k {)}^{2} = {r}^{2}$

where (h,k) is the centre coordinate and r is redious of the circle

given that, h=-2 , k=-5 and r=1

Thus substitute:

$\rm\displaystyle (x - ( - 2){)}^{2} + (y - ( - 5) {)}^{2} = {1}^{2}$

simplify:

$\rm\displaystyle (x + 2{)}^{2} + (y + 5 {)}^{2} = {1}^{}$

<h3>QUESTION-2:</h3>

Likewise

$\rm\displaystyle E _{c} :(x - h {)}^{2} + (y - k {)}^{2} = {r}^{2}$

given that,h=7,k=-3 and r=√7

substitute:

$\rm\displaystyle (x - (7{))}^{2} + (y - ( - 3){)}^{2} = { \sqrt{7} ^{2} }$

simplify:

$\rm\displaystyle (x - 7{)}^{2} + (y + 3{)}^{2} = { 7 }$

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2 years ago