I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
(x + a) (x + b) = x² + (a + b) x + ab
75 * 77=
=(70+5)(70+7)
=70²+(5+7)*70+5*7
=4900+12*70+35
=4900+840+35
=5775
Answer: B. The United States might not have been able to stop the attacks, but it could have made a better effort to do so.
Step-by-step explanation:
Answer: D
Step-by-step explanation:
First I would write out the points of the x and y intercepts and then I would write out an equation in slope-intercept form (y=mx+b). From there I would move my terms accordingly to make it into standard form and compare my answer! Hope this helped!
