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motikmotik
3 years ago
7

It is an unfair coin with unknown probability of head and tail. Can you generate even odds using this coin?

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0

Answer:

Yes, it can be generated if p = \frac{n}{n+1}, where n is a positive even integer.

Step-by-step explanation:

An odds for an event, is the probability or chance that this event will occur, divided by the probability that it will not occur.

Assume that the probability of getting tail when throwing the coin is p, therefore, the probability of getting a head is (1-p) and the odds for the event of getting tail is \frac{p}{1-p}.

If k is a positive integer, and we assume that the odds of getting a tail are even, then:

\frac{p}{1-p} = 2k

p = 2k - 2kp

p = \frac{2k}{2k+1}

Conclusion: if p = \frac{2k}{2k+1}, for some positive integer k, even odds are generated. For example: p = 2/3, 4/5, 6/7, ...

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The value k needed for the transformation of f(x) to g(x) = f(k · x) is equal to 3.056.

<h3>How to find the find the dilation factor</h3>

In this problem we have the following relationship bewteen the two <em>quadratic</em> equations: g(x) = f(k · x), which means that for all y the following relationship between f(x) and g(x):

k = \frac{x_{g}}{x_{f}}

Let suppose that y = 3, then x_{f} = - 5.5 and x_{g} = - 1.8, then the value k is:

k = (- 5.5)/(- 1.8)

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The value k needed for the transformation of f(x) to g(x) = f(k · x) is equal to 3.056.

To learn more on transformations: brainly.com/question/11709244

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6 0
1 year ago
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frosja888 [35]
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3 years ago
The basketball coach make up a game to play where each game takes. 10 shots at the basket. For every basket made, the player gai
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