Ask question

Ask question

All categories

2 years ago

8

looking for someone to help me with math on ixl its 7th grade math pls leave a comment saying youll help and ill comment my logi

n info pls help

1 answer:

yulyashka [42]2 years ago

6 0

Answer:

No don't give that out

Step-by-step explanation:

Never give out your login info. Just tell me what the question is

You might be interested in

How to solve function operations

Mama L [17]

" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google

3 0

2 years ago

Write each fraction as a decimal. Use bar notation if necessary odds only

bija089 [108]

Answer:number one=0.4667 and two is 0.44444444444

Step-by-step explanation:

4 0

2 years ago

How do you solve 10+5(3x-4)=2x+7

Taya2010 [7]

Answer:

$x=1\dfrac{4}{13}$

Step-by-step explanation:

Given the equation

$10+5(3x-4)=2x+7$

Use distributive property:

$10+5\cdot 3x-5\cdot 4=2x+7\\ \\10+15x-20=2x+7$

Use commutative property to rewrite the equation:

$15x+10-20=2x+7$

$15x-10=2x+7$

Add 10 th both sides:

$15x-10+10=2x+7+10\\ \\15x=2x+17$

Subtract $2x:$

$15x-2x=2x+17-2x\\ \\13x=17$

Divide by 13:

$x=\dfrac{17}{13}=1\dfrac{4}{13}$

4 0

3 years ago

Help ASAP!!!<br> Please and thank you so much

PilotLPTM [1.2K]

Rectangle on the left = 3 × 4 = 12

Rectangle in the middle = 3 × 2 = 6

Rectangle on the right = 4 × 3 = 12

Add:

12 + 6 + 12 = 30

Answer = 30

Hope this helped☺☺

8 0

2 years ago

Read 2 more answers

Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c

steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

Compute the sample proportions as follows:

$\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23$

The critical value of <em>z</em> for 90% confidence interval is:

$z_{0.10/2}=z_{0.05}=1.645$

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

$=(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)$

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0

2 years ago