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liq [111]
3 years ago
8

looking for someone to help me with math on ixl its 7th grade math pls leave a comment saying youll help and ill comment my logi

n info pls help
Mathematics
1 answer:
yulyashka [42]3 years ago
6 0

Answer:

No don't give that out

Step-by-step explanation:

Never give out your login info. Just tell me what the question is

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Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm. ​
Kobotan [32]

Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

A=\frac{bh_b}{2}

h_b=\sqrt{a^2-\frac{b^2}{4} }

There are 2 solutions for b

b=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } } ≈ 10cmb=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

4 0
2 years ago
a father is 10 times as old as his son. in 5 years he will be 5 times as old as his son. how old is the father and the son now
inn [45]

Answer:

The father is 40 and the son is 4.

Step-by-step explanation:

40 + 5 = 45.

4 +5=9.

45 divided by 5 = 9

5 0
4 years ago
(2x-3)(4-3x) Find the product of the binomials
kobusy [5.1K]
(2X-3)(4-3X)
=8X-6X²-12+9X
=-6X²+17X-12
That's your answer.
7 0
3 years ago
Read 2 more answers
What are the x- and y-intercepts for a line with one point at (2,1) and another at (6,3)?​
OverLord2011 [107]

Answer:

x - intercept = 0 and y - intercept = 0

Step-by-step explanation:

Using the two point slope intercept form, the formula is;

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

We are given the intercepts to be at

(2,1) and (6,3).

So, x1 = 2 and x2 = 6,while y1 = 1 and y2 = 3

Plugging into the equation, we have;

(y - 1)/(x - 2) = (3 - 1)/(6 - 2)

(y - 1)/(x - 2) = 2/4

(y - 1)/(x - 2) = 1/2

Cross multiply to get;

2(y - 1) = x - 2

2y - 2 = x - 2

2y = x

Now, the x intercept will occur at y = 0.

Thus,

2(0) = x

x = 0

Also, the y intercept occurs when x = 0.

So, 2y = 0

y = 0

x - intercept occurs at (0,0) and y - intercept occurs at (0,0)

5 0
3 years ago
Vă rog rezolvați-mi și mie aceste calcule:<br> Mersii
Akimi4 [234]
Fix you some claculations?
3 0
3 years ago
Read 2 more answers
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