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2 years ago

Garrett can order stickers from two

Mathematics

1 answer:

e-lub [12.9K]2 years ago

3 0

To have the same cost at both companies, the number of stickers will have to be 40

Company A :

Design Fee = $30

Costvper sticker = $0.80

Company B :

Design Fee = $14

Cost per sticker = $1.20

Let the number of stickers = p

Total cost of company A = 30 + 0.80p

Total cost of company B = 14 + 1.20p

For the cost to be the same :

Company A = Company B

30 + 0.80p = 14 + 1.20p

Collect like terms :

30 - 14 = 1.20p - 0.80p

16 = 0.40p

Divide both sides by 0.40

p = 16/0.40

p = 40 stickers

Therefore, to have the same price, 40 stickers will have to be ordered.

Learn more : brainly.com/question/13218948

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2 years ago

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Andreyy89

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4 0

2 years ago

Help please!!!!!!!!!

In-s [12.5K]

ANSWER

EXPLANATION

For a matrix A of order n×n, the cofactor $C_{ij}$ of element $a_{ij}$ is defined to be

$C_{ij} = (-1)^{i+j} M_{ij}$

$M_{ij}$ is the minor of element $a_{ij}$ equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.

Here, we have

$C_{11} = (-1)^{1+1} M_{11} = M_{11}$

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \end{aligned}$