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2 years ago

Garrett can order stickers from two

Mathematics

1 answer:

e-lub [12.9K]2 years ago

3 0

To have the same cost at both companies, the number of stickers will have to be 40

Company A :

Design Fee = $30

Costvper sticker = $0.80

Company B :

Design Fee = $14

Cost per sticker = $1.20

Let the number of stickers = p

Total cost of company A = 30 + 0.80p

Total cost of company B = 14 + 1.20p

For the cost to be the same :

Company A = Company B

30 + 0.80p = 14 + 1.20p

Collect like terms :

30 - 14 = 1.20p - 0.80p

16 = 0.40p

Divide both sides by 0.40

p = 16/0.40

p = 40 stickers

Therefore, to have the same price, 40 stickers will have to be ordered.

Learn more : brainly.com/question/13218948

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Answer:

Step-by-step explanation:

The prices are inconsistent, so there is no unique price that can be set for either an apple or an orange that will give the total prices indicated.

The first relation can be written as ...

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$10 = 4(A +O) . . . . factor out 4

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2 years ago

Choose the set of numbers with an average of 8.

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The correct answer is B

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What is -3 (6x -4) + 2 (2x -4) = - 50

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Answer:

$\frac{27}{7}$

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If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$