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aev [14]
3 years ago
10

Which congruence theorems or post

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

You can use:

1. LA theorem, because you have

  • leg ED is congruent to leg KJ;
  • ∠FED is congruent to ∠LKJ.

2. AAS Postulate, because

  • side ED is congruent to side KJ;
  • ∠FED is congruent to ∠LKJ;
  • ∠EFD is congruent to ∠KLJ.

3. ASA Postulate, because

  • side ED is congruent to side KJ;
  • ∠FED is congruent to ∠LKJ;
  • ∠EDF is congruent to ∠KJL.
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3/4 divided by 8

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Please help me with this
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3/5

Step-by-step explanation:

I just looked up how to do this since I've never done it before, so if I'm wrong I'm sorry, but from what I found all you have to do is put the opposite(o) over the hypotenuse(h) o/h which would be 9/15 and simplified it would be 3/5, and again if I'm wrong I'm sorry.

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I made a square frame for my favorite bird picture from four wooden pieces. Each piece is a rectangle with a perimeter of 24 inc
kupik [55]

Answer:

The perimeter of the picture frame is 38.4 in.

The area of the picture frame is 92.6 in.².

Step-by-step explanation:

The given information are;

Perimeter of side piece of picture frame = 24 inches

Length of side piece = L

Width of side piece = W

Perimeter of side piece = 2 × (L + W) = 24

∴ L + W = 24/2 = 12 inches

Dimension of picture frame = Square frame with side length s

Number of side piece in picture frame = 4

Given that the length L > the width W, we have

Side length of wooden frame = L

Also, where the side piece are placed side by side, we have;

Side length of wooden frame = 4 × W

Therefore;

4 × W = L

Which gives

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4 × W + W = 12 inches

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W = 12/5 = 2.4 inches

L = 4 × W = 4 × 12/5

L = 48/5 = 9.6 inches  Side length of wooden frame, s

The perimeter of the picture frame = 4 × s = 4 × 9.6 = 38.4 in.

The area of the picture frame = s × s = 9.6 × 9.6 = 92.6 in.².

7 0
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