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shtirl [24]
3 years ago
14

2 the function f(x)=-x+4x-3

Mathematics
1 answer:
Hunter-Best [27]3 years ago
5 0

The function of f(x)=-x+4x-3 is 3x-3. I hope this helps. :)
You might be interested in
Please I need help asap
jasenka [17]

Answer:

Option D - x = 3 3/5

Step-by-step explanation:

Lets make the left side into an improper fraction :

2 2/5 = 12/5

Now let's make both fraction into equivalent ones but with the same denominator :

2/3 = 10/15

12/5 = 36/15

Now we substitute the equivalent values back into the equation :

10/15 × x = 36/15

Now we multiply both sides by 15 to remove the denominators:

10 × x = 36

Now we divide both sides by 10 and simplify :

x = 36/10

x = 18/5

x = 3 3/5

So our answer will be Option D  

Hope this helped and brainliest please

7 0
2 years ago
Find each missing angle <br> Please
-BARSIC- [3]

Answer:

m<1=61

m<2=40

m<3=60

m<4=80

m<5=100

Step-by-step explanation:

180/3=60

180/9=20

20x2=40

20x4=80

20x3=60

59+60=119

180-119=61

180-80=100

7 0
3 years ago
Plz do have mercy and help me
Nikitich [7]
I have mercy:

8x and 9x+5 (the angles) form a right angle so 8x+9x+5=90 which means x is 5 and plugging it back into the angles 8x we get 40 sinceBHR and angle 8x are vertical angles they are equal to each other and so it's equal to 40
4 0
3 years ago
How does Roosevelt use appeals to convince the
Bad White [126]

Answer:

Roosevelt appeals to the logic of the audience by noting that the interests of the people are not considered in a one-party government.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the
Arisa [49]
:<span>  </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)). 

There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned. 

Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".

Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s. 

Plugging in t = 169 gives 2/13 cm3/s.</span>
4 0
3 years ago
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