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Fofino [41]
3 years ago
9

Find the area of the following polygons:

Mathematics
2 answers:
Art [367]3 years ago
8 0
Area of ABCE:
12 x 4
= 48cm squared

Area of CDE:
To get the height of the triangle, you subtract 4 from 10.

10 - 4 = 6cm
Base = 12 cm

12 x 6 = 72cm

72 divided by 2
= 36cm squared.

48 + 36 = 84cm squared.

(if it’s asking individual areas, then it’s 48cm and 36cm)
Fiesta28 [93]3 years ago
3 0

Answer:

84 m²

Step-by-step explanation:

The polygon is composed of a rectangle and a triangle.

area of rectangle = 12 × 4 = 48 m²

area of triangle = \frac{1}{2} × 12 × (10 - 4) = 6 ×6 = 36 m²

Total area = 48 + 36 = 84 m²

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The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.

\begin{gathered} 4y-2=90 \\ 4y=92 \\ y=23 \end{gathered}

The value of y is 23.

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\begin{gathered} 3x=45 \\ x=15 \end{gathered}

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\begin{gathered} 12z=45 \\ z=3.75 \end{gathered}

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8/9

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The equation to find a slope is y2-y1/x2-x1=m. (m is the slope)

174-166/173-164

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Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


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\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


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5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


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b^2+a^2=c(e+d).


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