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Pavel [41]
2 years ago
9

Find the integer that lies between

101%7D%24" id="TexFormula1" title="$\sqrt[3]{-45}$ and $\sqrt[3]{-101}$" alt="$\sqrt[3]{-45}$ and $\sqrt[3]{-101}$" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
4 0

∛(-45) = ∛((-1) × 45) = ∛(-1) × ∛45 = -∛45

Similarly,

∛(-101) = - ∛101

Now,

• 3³ = 27 and 4³ = 64, and 27 < 46 < 64, so ∛27 < ∛45 < ∛64, which places ∛45 between 3 and 4

• 5³ = 125, so ∛101 would similarly fall between 4 and 5

So to summarize, we have

3 < ∛45 < 4 < ∛101 < 5

so that

-5 < ∛(-45) < -4 < ∛(-101) < -3

so the integer between these numbers is -4.

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Pre cal/cal master needed
weqwewe [10]
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located 
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2 
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2  =  x^2 -4x + 4
2(x-2)^2  =  2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2 

Now lets put it all together 
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms 
2x^2 - 8x + 8 + 3x - 6 - 2
Combine:  2x^2      =  2x^2 
Combine: -8x + 3x  =  -5x
Combine:  8 - 6 - 2 =   0

So all we have left is
2x^2 - 5x





5 0
3 years ago
Help me plsssssssssssssssss
velikii [3]

Answer:

h=12

Step-by-step explanation:

by cross multiplying we get 1h=12 or h=12 so h=12

8 0
2 years ago
What does x equal in this equation -5x + 8 = -2
AnnyKZ [126]

Answer:

x = 2

Step-by-step explanation:

-5x + 8 = -2

-5x + 8 - 8 = -2 -8

-5x = -10

-5x/5 = -10/5

-x = -2

x=2

8 0
2 years ago
Read 2 more answers
28 6500 as a decimal
algol [13]

Answer:

.0043076923076923

Step-by-step explanation:

7 0
2 years ago
Write an equation for the line in point slope form through the points (2, −6) and (−1, −8).
igomit [66]

Let point A be (2, -6) and point B (-1, -8)

m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-8 - (-6)}{-1 - 2} = \frac{-8 + 6}{-1 -2} = \frac{-2}{-3} = \frac{2}{3}

Use the point-slope formula and whichever point you want as , in this case I'll use

y - y_1 = m(x - x_1)\\y - (-6) = \frac{2}{3}(x - 2)\\y + 6 = \frac{2}{3}x - \frac{4}{3}\\y = \frac{2}{3}x - \frac{4}{3} - 6\\y = \frac{2}{3}x - \frac{14}{3}

8 0
2 years ago
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