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Ulleksa [173]
3 years ago
15

Which of the following accurately depicts the transformation of y= x^2 to the function shown below? y=2(x-3)^2+5

Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

Which of the following accurately depicts the transformation of y= x^2 to the function shown below? y=2(x-3)^2+5

A. Shift left 3 units, shrink vertically to 1/2 of the original height, then shift up 5 units.

B. Shift right 3 units, stretch vertically by a factor of 2, then shift up 5 units.

C. Shift up 3 units, stretch horizontally by a factor of 2, then shift left 5 units.

D. Shift 5 units right, stretch vertically by a factor of 3, then shift up 2 units.

Step-by-step explanation:

For f(x) = 4x+1 and g(x)= x^2-5, find (f/g) (x).

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How do you do this question?
vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0
3 years ago
HELPP FAST WILL GIVE BRAINLIEST ANSWER AND WRITE SOMETHING NICE ON PROFILE!!
Temka [501]
#3)answer is choice D.77+W<_95;W<_18
#4)answer is choice A. t<7
7 0
3 years ago
Read 2 more answers
HELP BEFO 7 PLEASE...
Kay [80]
160ft3

Hope this helps

6 0
2 years ago
Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)
andrew11 [14]
Use the distance formula.

\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
Points S and W.
\sqrt{(3)^2 + (2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

\sqrt{10}

~3.1

Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

\sqrt{16}

~4

Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

\sqrt{(1)^2 + (-3)^2}

\sqrt{2+9}

\sqrt{11}

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
4 0
4 years ago
What value of x is in the solution set of 2x-3 &gt; 11 - 5x?
just olya [345]
2x-3 > 11 - 5x
2x + 5x > 11 + 3
7x > 14
x > 14/7
x > 2
3 0
3 years ago
Read 2 more answers
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