Given data:
Diameter of the gold wire (d) = 0.175 cm
Length of the gold wire (l) = 1.00 * 
cm
Volume of the given gold wire = volume occupied by a cylindrical object\
= π * 
*l
here r = radius of the cross section
where : r = d/2
Hence the volume V = π * 
*l
= 
Density of gold = 19.3 g/cm3
Weight of the gold wire = Density * volume
= 
* 
= 
Answer:
The first valence electron is removed.
Explanation:
Ionization energy is the energy that is needed to tear out the last electron of an atom in its ground state or gaseous state.
A(g) + IE ----> A+(g) + 1e-
When we talk about starting an electron we refer to the last valence electron, since it is the one that is furthest from the atomic nucleus, the one that does not feel attracted. As the question asks us the opposite, the ionization energy is going to be extremely high, if the electron to be removed occupies the first valence layer, since it is totally attracted to the nucleus.
Atoms are real even though they're invisible.
PbCl2 and PbCl4
Empirical formula is when the molecular formula is reduced (each element) by the same number until you are unable to do so any further.
CH2O cannot be further reduced, but C3H6O3 can all be divided by 3 making it CH2O (same empirical formula)
