Answer:

Explanation:
Hello,
By developing the following stoichiometric relationship, the required amount could be found as follows:
- Moles of
:

- Grams of 

- Moles of water:

Finally, one could see that the mass of the anhydrous compound is less than the pentahydrated compound since it is waterless.
Best regards.
I think D im not completely sure
Answer:
V2 = 17371.43ml
Explanation:
We use Boyles laws
since temperature is constant
P1V1=P2V2
760 x 400 = 17.5 x V2
304000 = 17.5 x V2
V2 = 304000/17.5
V2 = 17371.43ml
Answer:
D.
because her right ear was closer to Michelle, who was the source of the sound
Answer:
1.332 meters per second. // 2.664 meters per second.
Explanation:
the slower person moved 33.3 meters, and the faster person moved 66.6 meters.
the slower person is moving 33.3 meters in 25 seconds, while the other person is moving 66.6 meters in 25 seconds
slower person moved 33.3/25 = 1.332 meters per second.
faster person moved 66.6/25 = 2.664 meters per second.