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2 years ago

What is the molecular geometry of COF2?

Chemistry

1 answer:

maxonik [38]2 years ago

5 0

Answer:

trigonal planar

Explanation:

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What is another name for a coefficient? this is for chemistry

krok68 [10]

Answer:

synergistic

Explanation:

Synergistic means: relating to the interaction or cooperation of two or more organizations, substances, or other agents to produce a combined effect greater than the sum of their separate effects

7 0

2 years ago

PLEASE HELP A HOMIIE

Allushta [10]

Answer:

Its the first one. The cells are arranged for structure.

Explanation:

Animal cells do not need to maintain a shape since out bodies do it for us. Plant cells need something for structure.

8 0

3 years ago

Please help me with this question! Am I right?

muminat

You are right!! Good job!!!

5 0

2 years ago

In the summer of 2016, the city of Columbus Dublin Road Water Treatment plan exceeded the regulatory level of nitrate, which is

Verizon [17]

Answer:

a) $10 mg NO_3^-/L$

b) $1.61*10^{-4}mol NO_3^-/L$

c) $2.26 mg N/L$

Carbon: $C=26.64 \frac{mg C}{L}$

Explanation:

Nitrate

First of all, is important to know that:

$1 ppm=1 mg/L$

a) 10 ppm of nitrate ( $NO_3^-$ ) is equal to $10 mg NO_3^-/L$

b) The molecular weight of nitrate is $62 g NO_3^-/mol$

$10 mg NO_3^-/L=0.01 g NO_3^-/L$

$\frac{0.01 g NO_3^-/L}{62 g NO_3^-/mol}=1.61*10^{-4} mol NO_3^-/L$

c) Nitrate has 14 mg of N per 62 mg of NO3

$10 mg NO_3^-/L*\frac{14 mg N}{62 mg NO_3^-}=2.26 mg N/L$

Carbon

Carbonate has 12 mg of C per 60 mg of $CO_3^{-2}$

Bicarbonate has 12 mg of C per 61 mg of $HCO_3^{-}$

$C=24 \frac{mg CO_3^{-2}}{L}*\frac{12 mg C}{60 mg CO_3^{-2}}+111 \frac{mg HCO_3^{-}}{L}*\frac{12 mg C}{61 mg HCO_3^{-}}$

$C=26.64 \frac{mg C}{L}$

8 0

2 years ago

Suppose a 10.0 L reaction vessel is filled with 0.86 mol of BrOCl and 0.86 mol of BrCl. What can you say about the composition o

kykrilka [37]

Answer:

With regards to the final composition of the mixture in the vessel at equilibrium, there will be very little amount of the reactants (BrOCl and BrCl), since some amounts of each have been used to form the products (Br2 and OCl).

4 0

3 years ago