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Juli2301 [7.4K]
4 years ago
6

Please help with the question

Chemistry
1 answer:
Ludmilka [50]4 years ago
3 0
Answer: NO2.

You can predict that two atoms with similar electronegativity will form covalent compounds while atoms with pretty different electronegativity will form ionic compounds.

Given that N and O are neighbors on the periodic table, you can predict they have similar electronegativities.

Also you can predict that from the fact that N and O are nonmetals, which also means that they will form covalent compounds.

The other compounds liste are formed by metals and non metals wich is an indication that they will have, at least, some ionic character.

Ergo, N and O will form covalent compounds, in this case NO2.
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Other oils, such as car oil and vegetable oil, also consist largely of bonded carbon and hydrogen atoms. Would you predict that
grigory [225]

Answer:

Car oil and vegetable oil will mix well with gasoline

Car oil and vegetable oil will not mix with water.

Explanation:

Car oil and vegetable oil will mix well with gasoline

Car oil and vegetable oil will not mix with water.

This is because of the rule of solubility. According to this rule, like substances will only dissolve like substances. In essence, a polar compound will only dissolve another polar compound. A non-polar compound will dissolve only in a non-polar solvent.

Water is polar and oil is non-polar. The cannot mix.

Gasoline is non-polar and will dissolve oil which is also non-polar .

7 0
3 years ago
The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
3 years ago
Read 2 more answers
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Answer:

Erosion

Explanation:

3 0
3 years ago
Can someone please help me
Alona [7]

Answer:

Potassium iodide increases the decomposition rate of hydrogen peroxide.

Explanation:

Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.

5 0
3 years ago
What is the difference between aluminum phosphide and aluminum phosphate?
lana [24]

Answer:

The answer is below

Explanation:

Here some of the difference between aluminum phosphide and aluminum phosphate

1. Aluminum phosphide is a crystalline solid with either dark gray or yellow color. While Aluminum Phosphate is in a nanopowder form but with a whitish color.

2. Aluminum phosphide is used in the fumigation of plants, while Aluminum phosphate is used in cosmetics, paints, etc.

3. Aluminum phosphide has a compound formula of AlP with a molar mass of 57.9552 g/mol, while Aluminum Phosphate has a compound formula of AlO4P with a molar mass of 121.9529 g/mol

7 0
3 years ago
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