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kiruha [24]
3 years ago
6

In order to have a contact force acting on an object, the force

Chemistry
1 answer:
Oliga [24]3 years ago
5 0
I believe the answer is C. (must be touching the object)

Someone please correct me if I am wrong.
You might be interested in
Part A
astraxan [27]

Answer

mass of 1 mole = 18g

mass of 1 mL = 1g

the unit used is gram

Explanation:

There are two ways to find mass of water:

1st way:

If we find Mass of water for one mole of water:

For this purpose we use mole formula as below

                          no. of moles = mass in grams / molar mass

if we find mass for one mole of water:

then

no. of moles of water = 1 mol

molar mass of water = H₂O = (1x2 +1x16) = 18 g/mol

mass of water = ?

Put the value in the mole formula

          no. of moles = mass in grams / molar mass . . . . . . . . . . . . (1)

by rearranging the formula (1)

            mass in grams = no. of moles x molar mass

            mass in grams = 1 mole x 18 g/mol

            mass in grams =  18 g

So for one mole of water the mass of water is 18 g and the unit for it is gram.

2nd way:

We can find mass of water by another way too

if we find the mass 1 mL of water

then the formula will be used is

                              D = m/v

where D is density

m is the mass

and v is the volume

So

density of water for 1 mL (D) = 1 g/ml

volume of water = 1 mL

mass of water = ?

By Rearranging density formula for mass

                                m = D/v ......................... (2)

put the values in equation 2

                                m= 1gmL⁻¹ / 1 mL

                                 m= 1g

So the mass of 1mL is 1g

7 0
3 years ago
A. At STP, what is the volume of 708 mol of nitrogen gas? 708 mol = 708 mol X L B. A sample of hydrogen gas occupies 14.1 L at S
elena-14-01-66 [18.8K]

Answer:

A. 15859.2 L or 15900 L

B. 0.629 mol

Explanation:

At STP, one mole is equal to approximately 22.4 L

L or mL is volume, so you are attempting to solve for L or mL.

A.

708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)

B.

(14.1 L) x (1 mole/ 22.4 L) = 0.629 mol.

5 0
2 years ago
The intermolecular forces between polymer molecules are strong, so these substances are __________ at room temperature. What wor
geniusboy [140]

Answer:

I want to say

Stronger

8 0
2 years ago
HURRY!!!!!!!!!!!!!!!!!!!!!!!WHAT TYPE OF STORM FORMS WHEN WINDS BEGIN TO ROTATE OVER OCEAN WATER BRINGING HIGH WINDS AND VERY HE
solmaris [256]
 the answer is a tsunami
7 0
2 years ago
What mass of zinc is needed to react with 23.1 g of phrosphoric acid according tot he equation?
Hitman42 [59]

<u>Complete Question:</u>

what mass of zinc is needed to react with 23.1 g of phosphoric acid according tot he equation?

3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂

<u>Answer:</u>

22.98 g, the mass of zinc (Zn) is needed to react with 23.1 g of phosphoric acid according to the given equation.

<u>Explanation:</u>

Given chemical reaction:

           3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂

If the substance’ molecular weight is the number of grams required per mole, the number of moles expressed as a given quantity of substances shall correspond to the grams of that substance divided by the molecular weight. Hence,

              \text {number of moles}=\frac{\text {mass}}{\text {molar weight}}

To find no. of moles of phosphoric acid:

Given:

mass of phosphoric acid = 23.1 g

molar weight of of phosphoric acid = 97.994 = 98 g/mole

Therefore,

no. of moles of phosphoric acid =\frac{23.1}{98}=0.2357 \text { moles }

Look into the given chemical reaction and divide as the following:

If 2 moles of H₃PO₄ reacts with 3 moles of Zn then 0.2357 moles of H₃PO₄ reacts with X moles of Zn. Then,

   \text { X moles of } \mathrm{Zn}=\frac{(0.2357 \times 3)}{2}=\frac{0.707}{2}=0.3535 \text { moles of } \mathrm{Zn}

Now, calculate mass of zinc as follows, we know

molar mass of zinc is 65 g/mol

 mass\ of\ zinc = number\ of\ moles \times molar\ weight =0.3535 \times 65

Mass of zinc = 22.98 g

7 0
3 years ago
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