If the solute is properly distributed in the given volume, there are 2.642 g of (NH4)2SO4 per 10 mL. For the new solution, divide the 2.642 g by the molar mass of the compound. The answer is 0.02 moles. Then, divide this by the new volume, 50 mL or 0.05 L. The concentration of the new solution is 0.4 M.

7 0

3 years ago

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What is Displacement reaction . Explain with an example.

jok3333 [9.3K]

Explanation:

A displacement reaction is the one wherein the atom or a set of atoms is displaced by another atom in a molecule. For instance, when iron is added to a copper sulphate solution, it displaces the copper metal. A + B-C → A-C + B.

6 0

3 years ago

How many sodium ions are present in 325 ml of 0.850 m na2so4?

NISA [10]

Answer:

$Na^+_{ions}=3.33x10^{23}Na^+_{ions}$

Explanation:

Hello,

In this case, for the given molarity and volume of such solution, the moles of sodium sulfate are computed below:

$n_{Na_2SO_4}=0.850\frac{mol}{L}*0.325L=0.276molNa_2SO_4$

Now, by using the Avogadro's number, the ions result:

$Na^+_{ions}=0.276molNa_2SO_4*\frac{2molNa^+}{1molNa_2SO_4} *\frac{6.022x10^{23}Na^+_{ions}}{1molNa^+} \\\\Na^+_{ions}=3.33x10^{23}Na^+_{ions}$

Best regards.

4 0

3 years ago

Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou

lesya [120]

First, let's compute the number of moles in the system assuming ideal gas behavior.

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>

3 0

4 years ago