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sukhopar [10]
3 years ago
12

John Dalton believed which of the following about atoms?

Chemistry
1 answer:
8090 [49]3 years ago
3 0
Atoms are real even though they're invisible.
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The uses of sodium phosphate include clarifying crude sugar, manufacturing paper, removing boiler scale, and washing concrete. W
garri49 [273]

2.4  ×    10⁻² is the pH of a solution

What is the short definition of pH?

  • The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
  • In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

Equation representing the i onization of Na₃PO₄ is as fallow

              Na₃PO₄          →                 PO₄³⁻    +  3Na⁺

Concentration of Na₃PO₄ = \frac{26.9 * \frac{1 mol}{164 g} }{1 L} = 0.164 M

Since 1 mol of Na₃PO₄ forms 1 mol of  PO₄³⁻  [  PO₄³⁻  ] = [ Na₃PO₄ ] = 0.164 M

Equation representing the  i onization of HPO²⁻₄ is as fallow

 HPO²⁻₄          →         PO₄³⁻  +    H⁺

Acidionization constant Ka₃ of   HPO²⁻₄  = 4. 17 ×  10⁻¹³

Baseionization constant  Kb₃ of  PO₄³⁻ = Ka₃/ Kb₃

                              = 1 .0  ×  10⁻¹⁴/  4. 17 ×  10⁻¹³  = 2.4  ×    10⁻²

Learn more about pH

brainly.com/question/15289741

#SPJ4

4 0
1 year ago
In the following reaction: Mg + 2HCl → MgCl2 + H2 How many liters of H2 would be produced if you started with 24.3 g of Mg?
Aloiza [94]

Answer:

22.4 L H2

Explanation:

There is a better explanation brainly.com/question/9562878

4 0
3 years ago
N2 + 3H2 - 2NH3
vladimir1956 [14]

The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles

<h3>How to determine the mole of NH₃ produced </h3>
  • Mass of NH₃ = 150 g
  • Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
  • Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 150 / 17

Mole of NH₃ = 8.82 moles

<h3>How to determine the mole of N₂ needed </h3>

Balanced equation

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

2 moles of NH₃ were produced by 1 mole of N₂.

Therefore,

8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.

Thus, 4.41 moles of N₂ is  needed for the reaction.

Learn more about stoichiometry:

brainly.com/question/14735801

4 0
2 years ago
How many grams of AgNO3 are needed to make 250 ml of a solution that is 0.135 M
myrzilka [38]

Answer:

( About ) 5.7 grams

Explanation:

Take a look at the attachment below for a proper explanation;

5 0
3 years ago
You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca
asambeis [7]
Answer is: <span>volume of balloon is </span>476,85 cm³.
density of air: d(air) = -0,0043 · 18,0°C + 1,2874.
d(air) = 1,21 kg/m³ = 1,21 · 10³/ 10⁶ = 0,00121 g/cm³.
m(balloon) = 0,577 g.
d(balloon) = d(air).
d(balloon) = m(balloon) ÷ V(balloon).
V(balloon) = m(balloon) ÷ d(balloon)
V(balloon) = 0,577 g ÷ 0,00121 g/cm³.
V(balloon) = 476,85 cm³.
8 0
3 years ago
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