Sin² x + sin x cos x = 0
sin x ( sin x + cos x ) = 0
sin x = 0 ; x 1 = k π ; k ∈ Z
sin x + cos x = 0 / ²
sin² x + 2 sin x cos x + cos² x = 0
2 sin x cos x + 1 =0
sin ( 2 x ) = - 1
x = 3π / 2 + 2 kπ / : 2
x 2 = 3π / 4 + kπ ; k ∈ Z
Answer:
x=2
Step-by-step explanation:
3(3 - 8x) - 1 = -6x - 28
Distribute
9 -24x -1 = -6x -28
Combine like terms
8 -24x = -6x -28
Add 24x to each side
8-24x+24x = -6x-28+24x
8 = 18x-28
Add 28 to each side
8+28 = 18x-28+28
36 = 18x
Divide each side by 18
36/18 = 18x/18
2 =x
APP IT will HELP SIDJIDNUDNUD
2(x^2+6x+9) = 2(x+3)^2
So after divided by (x+3), answer will be:
2(x+3)