Answer:
-8y+5=37
-8y= 37-5
-8y= 32
y= 32/-8
y= -4
Step-by-step explanation:
Distance=rate .time
The rate of car 1 is 45km/hr
The rate of 2 car is 70/hr
We know that the second car left two hours after the first
If we let car 1 time =x
Then the time of second car=x-2
When two car reach the landmark,
The distance traveled by each will be the same
Therefore let us set up our equation using the formula for distance
Distance of car 1 = 45*x=45x
Distance of 2 car = 70(x-2)
=70x-140
Set these two equals to each other to designate when they reach the landmark
45x=70x-140
-25x=-140
X=140/25=28/5
=5 3/5
The time traveled by car 2 in the same direction
=v-2=(5 3/5-)-2= 3 3/5 hours
After 3 3/5 hours, car will be overtake car 1
It is substitution. Because you are substituting 3=y into x+5=3
Answer:
See below
Step-by-step explanation:
1. During which time period is Kelly's heart rate increasing? (1 point)
2. Using math, determine the exact rate of change for the increase (warm‐up). Explain how you got your answer. (3 points; 1 point for answering the question, 2 points for explaining your answer)
-
Rate of change = Change in y / change in x
- (115 - 65)/(15-0) = 50/15 = 3.33
3. During which time period did Kelly's heart rate remain constant? (1 point)
4. Using math, determine the exact rate of change for this time period. Explain how you got your answer. (3 points; 1 point for answering the question, 2 points for explaining your answer)
-
ROC = (115 - 115)/(35 - 15) = 0
5. During which time period did Kelly's heart rate decrease? (1 point)
6. Using math, determine the exact rate of change for the decrease (cool down). Explain how you got your answer. (3 points; 1 point for answering the question, 2 points for explaining your answer)
-
ROC = (70 - 115)/(45 - 35) = - 45/10 = -4.5
7. Explain why your rate of change for the cool down period was a negative value. (2 points)
- Negative rate indicates drop in heart rate during cool down