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PtichkaEL [24]
2 years ago
5

I don’t know how to do this question

Mathematics
1 answer:
noname [10]2 years ago
5 0
Can you post link cause there’s no question
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I think z because if you flip the shape around it will create the same shape as z
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Compound interest compounded quarterly is given every ______ months. *<br> 1 point<br> 1<br> 3<br> 6
Ipatiy [6.2K]

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3 months

a quarter is a period of three months

Step-by-step explanation:

7 0
3 years ago
Find the mean of the first 7 odd prime number?​
bekas [8.4K]

Answer: 75/7 or 10.71 (rounded)

Step-by-step explanation:

Mean = Average

To find the average you should add all the numbers together and then divide it by the amount of numbers.

In this question, the formula is \frac{n_1+n_2+n_3+n_4+n_5+n_6+n_7}{7}

----------------------------------------------------------------------------------------

The list of the first 7 odd prime numbers:

3, 5, 7, 11, 13, 17, 19

Now, add them together

3+5+7+11+13+17+19=75

Divide the sum by 7

75÷7=75/7=10.71 (rounded)

Hope this helps!! :)

Please let me know if you have any questions

6 0
3 years ago
Which of these statements is true for f(x)=5x(6)^x
bonufazy [111]

Answer:

The answer if B. Hope this helps.

Step-by-step explanation:

3 0
3 years ago
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Cancel the common factor of the numerator and the denominator and write specified expression
lisabon 2012 [21]

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

3 0
3 years ago
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