Answer:
Step-by-step explanation:
Let the length and breadth of the rectangle be a,b units respectively.
Then the area will be ab square units.
Now if the length of the rectangle is reduced by 5 units and breadth is increased by 2 units then new length and breadth will be (a−5) units and (b+2) units.
Then new area will be (a−5)(b+2).
Then according to the problem,
(a−5)(b+2)−ab=−80
or, 2a−5b=−70.......(1).
Now if length of the rectangle is increased by 10 units and breadth is decreased by 5 units then new length and breadth will be (a+10) units and (b−5) units.
Then new area will be (a+10)(b−5).
Then according to the problem,
(a+10)(b−5)−ab=50
or, 10b−5a=100
or, 2b−a=20
or, 4b−2a=40......(2).
Now adding (1) and (2) we get
−b=−30
or, b=30.
Putting the value of b in (1) we get, a=40.
Now a+b=40+30=70.
I did a bit of it then put it in a calculator and got 0.512269939
Answer:
13
Step-by-step explanation:
Divide:
27 ÷ 2 = 13 r1
So, he can buy 13 but has a dollar left.
Hope this helps you out! : )
Find coterminal angles Ac to a given angle A.
What are coterminal angles?
If you graph angles x = 30o and y = - 330o in standard position, these angles will have the same terminal side. See figure below.
<span><span><span> </span> </span> </span>
Coterminal angles Ac to angle A may be obtained by adding or subtracting k*360 degrees or k* (2 Pi). Hence
Ac = A + k*360o if A is given in degrees.
or
Ac = A + k*(2 PI) if A is given in radians.
where k is any negative or positive integer.
Example 1: Find a positive and a negative coterminal angles to angle A = -200<span>o</span>
