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11111nata11111 [884]
2 years ago
9

Can someone pls help me

Mathematics
1 answer:
nevsk [136]2 years ago
7 0

\huge\text{Hey there!}

\huge\textsf{Your GUIDE}\huge\downarrow

\large\text{The DISTRIBUTIVE FORMULA is......}\\\large\text{a(b + c)}\\\large\text{a(b) + a(c)}}\\\large\text{a(b) = ab}\\\large\text{a(c)=ac}\\\large\text{= \underline{ab + ac}}

\text{Now lets SOLVE for your QUESTION, shall we?}}

\large\text{\bf{9(2n +1)}}\\ \large\text{\bf{9(2n) +9(1)}}\\\arge\text{\bf{9(2n)=18n}}\\\large\text{\bf{9(1)=9}}\\\large\text{\bf{= \underline{18n+9}}}}

\boxed{\boxed{\bold{Answer: 18n +9}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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Find the 99th term of the arithmetic sequence 2, -3, -8,...
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Answer:

the sequence is by -5

therefore the next numbers are

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3 years ago
Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
3 years ago
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1,2,4 are functions
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Read 2 more answers
If s(t) =60/t, to find s(10), substitute 10 in for t, to get 60/10= 6<br><br> TRUE OR FALSE
iogann1982 [59]

Answer:

THE ANSWER IS TRUE

Step-by-step explanation:

5 0
3 years ago
Y is inversley proportionaly to x. when y=7, x=9
mrs_skeptik [129]

The equation is y = 63/x

And y = 3 when x=21

Step-by-step explanation:

When y varies inversely with x, The inverse proportion is given by:

y ∝1/x

When the proportionality symbol is removed, a constant of proportionality is introduced

y = \frac{k}{x}

Putting y = 7 and x = 9

7 = \frac{k}{9}\\k = 9*7\\k = 63

So,

y = \frac{63}{x}

Putting x =21

y = \frac{63}{21}\\y = 3

Hence,

The equation is y = 63/x

And y = 3 when x=21

Keywords: Proportion, variables

Learn more about proportion at:

  • brainly.com/question/11220787
  • brainly.com/question/11131690

#LearnwithBrainly

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