The percentage of data that is roughly greater than 66, as displayed in the box plot, is 100%.
<h3>How to Determine a Percentage of a Data Represented in a Box Plot?</h3>
In a box plot, we have the following displayed five-number summary which tells what percentage of the data distribution for each part of the data distribution:
Upper quartile (Q3): This is the value at where the box in the box plot ends at the edge of the box. From this point to the left, all data values that fall within the bracket make up 75% of the data.
Lower quartile (Q3): This is the value at where the box in the box plot starts at the edge of the box. From this point to the left, all data values that fall within the bracket make up 25% of the data.
Median: this is the middle value at the point where the line divides the box and data below this point make up 50% of the data.
The other five-number summary are the maximum and the minimum values that are represented by the whiskers.
On the box plot given, 66 is at the extreme whisker at the left. This means that the percentage of data that is roughly greater than 66 is 100%.
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Answer:
x = 67.50 ft
Step-by-step explanation:
Consider, ΔMAB and ΔMNP,
∠M = ∠M (Common)
Given AB║NP and let MN as transversal,
∠MAB = ∠MNP (alternate angle)
Also, Given AB║NP and let MP as transversal,
∠MBA = ∠MPN (alternate angle)
Therefore, ΔMAB ≅ ΔMNP (By AAA similarity )
Thus, by CPCT,
consider first two ratios,
Substitute the values, MA = MN - AN = 49.5 ft
On solving for x , we get, x = 67.50 ft
Thus, value of x is 67.50 ft
Set 40 = 5x + 10
Subtract 10 on both sides, then divide 30 by 5
x = 6
