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2 years ago

What is a product of power?

Mathematics

2 answers:

Kryger [21]2 years ago

6 0

Answer:

To find a power of a product, find the power of each factor and then multiply. In general, (ab)m=am⋅bm. am⋅bm=(ab)m. In other words, you can keep the exponent the same and multiply the bases.

Step-by-step explanation:

We use the power of a product rule when there are more than one variables being multiplied together and raised to a power. The power of a product rule tells us that we can simplify a power of a power by multiplying the exponents and keeping the same base.

natka813 [3]2 years ago

3 0

Answer:

dunno if this will help but

Step-by-step explanation:

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What is the domain of this function in the graph below? What is the interval?

Maurinko [17]

Domain in interval: [6,infinity)

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2 years ago

Express the product in simplest form.

Dmitry [639]

The product in simplest form is (x - 4)

Solution:

Given expression is:

$\frac{8}{2x+8} \times \frac{x^2-16}{4}$

We have to find the product in simplest form

In the given expression,

2x + 8 = 2(x+ 4)

We know that,

$a^2-b^2=(a+b)(a-b)$

Therefore,

$x^2-16 = x^2-4^2 =(x+4)(x-4)$

Substitute these in given expression

$\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4}$

Cancel the common factors,

$\frac{8}{2(x+4)} \times \frac{(x+4)(x-4)}{4} = x - 4$

Thus the product in simplest form is (x - 4)

8 0

2 years ago

4. What’s the answer to this question?!

telo118 [61]

Answer:

2000

Step-by-step explanation:

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3 years ago

The sum of two consecutive integers is 201 find the integers

telo118 [61]

100 and 101

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8 0

2 years ago

Read 2 more answers

In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th

MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

$\frac{20!}{18!2!}=190$

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0

2 years ago