The radius is 6 feet. The radius will always be half of whatever the diameter is
<span>2 times 10 squared to the second power in standard notation
2 x(10^2)^2
=2x10^4
=20000</span>
Answer:
25, -25
Step-by-step explanation:
This is the answer. It's simple. Just think of the two lines next to the number and that can be -25 and 25.
Answer:
78.10 cm^2
Step-by-step explanation:
The area of the shaded region is the area of the rectangle subtracted from the area of the circle.
area of circle = (pi)r^2
area of rectangle = LW
shaded area = area of circle - area of rectangle
shaded area = (pi)r^2 - LW
shaded area = (pi)r^2 - LW
shaded area = (3.14159)(6 cm)^2 - (7 cm)(5 cm)
shaded area = (3.14159)(36 cm^) - 35 cm^2
shaded area = 113.097 cm^2 35 cm^2
shaded area = 78.097 cm^2
Answer: 78.10 cm^2
Answer:
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.
This means that 
Find the probability that one selected subcomponent is longer than 118 cm.
This is 1 subtracted by the pvalue of Z when X = 118. So



has a pvalue of 0.6443
1 - 0.6443 = 0.3557
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.