So, the anti derivative= x^2 -.8x +C. Ignore C.
Plug in 2= 4-(2)(.8)=2.4
Plug in .4= .16-(.4)(.8)=-.16
2.4-(-.16)= 2.56
Answer:
Option B
Step-by-step explanation:
we know that
A line perpendicular to the x-axis is a line parallel to the y-axis
so
the equation of the line is of the form x=(+/-)a
The slope of the line is undefined
where
a is a real number
therefore
x=6 is a line perpendicular to the x-axis
Given parameters:
Coordinates of end points = (2, -3) and (-6,5).
Slope of line =
Unknown:
Equation of the line with the given slope = ?
Solution:
Let us find the coordinates of the mid-point of the line given.
Since the end points are (2, -3) and (-6,5);
Midpoint;
x, y = ,
x, y = , = -2 , 1
The coordinate of the mid point = -2,1
Equation of a line is;
y = mx + c
x and y are the coordinates
m is the slope
c is the y intercept
We need to find c in order to fully develop our equation;
y = mx + c
y = 1 , x = -2 and m =
So,
1 = x (-2) + c
c = 1 + =
Now, the equation of the line is;
y = -2x +
Multiply through by 7,
7y = -14x + 25
The equation of the line is 7y = -14x + 25
-35 = h
To get rid of fractions you simply multiply the denominator to the whole equation. -7 =h/5 can be -7(5) = (h/5)(5)
(2x^2-x-6)/x^2-4
Factor top and bottom and you get
(2x+3)(x-2)/(x+2)(x-2)
The (x-2) cancel out each other leaving,
(2x+3)/x+2
The domain is all real numbers EXCEPT for -2. The domain can never be -2 as it would to the bottom having a zero, and that can't happen