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bixtya [17]
3 years ago
7

Is 8.23 a rational number?

Mathematics
2 answers:
aalyn [17]3 years ago
5 0
Yes, it is a rational number because 8.23 can be expressed as a fraction.
Leni [432]3 years ago
3 0
Yes, 8.23 is a rational number since it is able to be written as a fraction (any rational number is able to be written as a fraction with an integer numerator and denominator); 8 23/100
You might be interested in
a parallelogram has a base of 3 feet and a height of 5 feet. The base and height will each be doubled. Will the area also be dou
navik [9.2K]

Answer:

No, doubling the base and height would actually quadruple the area,

Step-by-step explanation:

With the original measurements of b = 3 ft and h = 5 ft,

<em>b x h = A</em>

<em>(3) x (5) = </em><em>15 ft</em>

So lets say we <em>doubled</em> the factors:

<em>(2)(3) x (2)(5) = A</em>

We would end up with 60 feet, four times that of 15.

<em>(6) x (10) = </em><em>60 ft</em>

3 0
3 years ago
Last week Jonas spent 9 1/6 hours working on his homework over a period of 4 2/3 days. Approximately how many hours a day, on av
Elina [12.6K]

Answer:

55/28 hours/day (approx.  1.96 hours/day)

Step-by-step explanation:

9 1/6 hours / 4 2/3 days

= 55/6 hours / 14/3 days

= 55/6 * 3/14 hours/day

= 55/28 hours/day

(approx.  1.96 hours/day)

3 0
3 years ago
I need help plz and thank u sm
Alchen [17]

Answer:

5x + 3

Step-by-step explanation:

Since we can see DC is the median of Triangle ABC

So it breaks the into two equal parts

Given

AD = 2x + 5

BD = 3x - 2

Now

AB = AB + BD

= 2x + 5 + 3x - 2

= 5x + 3

Hope it will help :)❤

7 0
2 years ago
The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room
tangare [24]
I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. 

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
A = lw\\&#10;600 = (x+5)(x+4)\\&#10;600 =  x^{2} + 9x + 20&#10;

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
600 = x^{2} + 9x + 20\\&#10;x^{2} + 9x - 580 = 0\\&#10;(x + 29)(x - 20) = 0\\&#10;x + 29 = 0, \:\: x - 20 = 0\\&#10;x = -29, x = 20

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).
8 0
3 years ago
Read 2 more answers
Help me with this question i tried multiple time to solution it always wrong
maw [93]
7/9-1/3 or 7/9-3/9= 4/9 is the answer
4 0
3 years ago
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