Answer:
u = 0.176 m/x
Explanation:
∴ n O2 = 1 mol
∴ mass O2 = 1 mol * 32 g/mol = 32 g
∴ T = 60°C = 333 K
∴ P = 5 bar
⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)
⇒ V = 5537.124 cm³
∴ d = 20cm
⇒ A = (1/4π)*d² = 314.16 cm²
velocity of the gas (m/x):
- u = m / ρ*A
- let time (t) = x sec
∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³
∴ mass flow rate (m) = 32g / x
⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))
⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x
Answer:
Standard reduction potential is an intensive property---- True
Reduction takes place at the anode ----- False
The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false
The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell ------ True
Explanation:
An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.
In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).
The mineral that you described is called Muscovite. The pages of the book description fits muscovite found in granite pegmatites where it is found in large crystals with a
pseudohexagonal outline that are called "books".
Answer:
Explanation:
Hello,
In this case, since the undergoing chemical reaction is:
The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:
Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:
Regards.
