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natka813 [3]
3 years ago
11

Explain what the horizontal and vertical lines of a Fischer Projection indicate about the structure of the molecule

Chemistry
1 answer:
gulaghasi [49]3 years ago
7 0

Explanation:

Fischer Projections allow to represent the three dimensional molecular structures in two dimensional environment without the change in the properties or the structural integrity of the compound. <u>It consists of horizontal as well as vertical lines both, where horizontal lines represent atoms which are pointed toward viewer while vertical line represents atoms which are pointed away from viewer. </u>The point of the intersection between horizontal and vertical lines represents central carbon.

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If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
goldfiish [28.3K]
The balanced chemical reaction:

<span>Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
</span>
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

9.85 g Cu ( 1 mol Cu / 63.55 g Cu ) = 0.15 mol Cu
31.0 g AgNO3 ( 1 mol AgNO3 / 169.87 g AgNO3 ) = 0.18 mol AgNO3

The limiting reactant is AgNO3.

0.18 mol AgNO3 ( 1 mol Cu(NO3)2 / 2 mol AgNO3 ) (187.56 g / 1 mol) =16.88 g Cu(NO3)2

0.15 mol Cu - 0.18 mol AgNO3 ( 1 mol Cu / 2 mol AgNo3) = 0.06 mol Cu excess

<span>0.06 mol Cu ( 63.55 g Cu / 1 mol Cu ) = 3.81 g Cu excess</span>
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3 years ago
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How many milliseconds are there in 3.5 seconds
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There are 3,500 milliseconds in 3.5 seconds. Hope this helps!
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3 years ago
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How many elements have been discovered?<br> A. 110 <br> B. less than 110 <br> C. more than 110
riadik2000 [5.3K]
There are 115 known elements as of today (Feb. 13, 2016)

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8 0
3 years ago
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Calculate the percent ionization of formic acid (hco2h) in a solution that is 0.311 m in formic acid and 0.189 m in sodium forma
ohaa [14]
<span>Answer: 0.094%


</span><span>Explanation:
</span>
<span></span><span /><span>
1) Equilibrium chemical equation:
</span><span />

<span>Only the ionization of the formic acid is the important part.
</span><span />

<span>HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq).
</span><span />

<span>2) Mass balance:
</span><span />

<span>                   HCOOH(aq)     HCOO⁻(aq)     H⁺(aq).

Start             0.311                 0.189

Reaction       - x                      +x                   +x

Final             0.311 - x          0.189 + x            x


3) Acid constant equation:
</span><span />

<span>Ka = [HCOO-] [N+] / [HCOOH] = (0.189 + x) x / (0.311 -x)
</span><span />

<span>= (0.189 + x )x / (0.311 - x) = 0.000177


4) Solve the equation:


You can solve it exactly (it will lead to a quadratic equation so you can use the quadratiic formula). I suggest to use the fact that x is much much smaller than 0.189 and 0.311.
</span><span />

<span>With that approximation the equation to solve becomes:


</span><span>0.1890x / 0.311 = 0.000177, which leads to:</span>
<span /><span>
x = 0.000177 x 0.311 / 0.189 = 2.91 x 10⁻⁴ M


5) With that number, the percent of ionization (alfa) is:
</span><span />

<span>percent of ionization = (moles ionized / initial moles) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (concentration of ions / initial concentration) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (0.000291 / 0.311)x 100 = 0.0936% = 0.094%
</span>
<span></span><span />
8 0
3 years ago
Which is the balanced single displacement reaction between Aluminum (Al3+) and Copper Sulfate (Cu2+(SO4)2-)
Aliun [14]

Answer:

The balanced single displacement reaction between aluminum and copper sulphate is as follows.

2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)

Explanation:

The given ions are as follows.

Al^{3+}- Aluminium ion and copper sulfate ion.

Single displacement reaction occurs one element replaces another element.

Hence, the balanced chemical reaction is as follows.

2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)

<u>Oxidation half reaction:</u>

Al\rightarrow Al^{3+}+3e^{-}

Aluminium loses three electrons.

<u>Reduction half reaction:</u>

<u>Cu^{2+}+2e^{-}\rightarrow Cu(s)</u>

Copper gain three electrons.

4 0
3 years ago
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