Answer:
copper will reach to higher temperature first.
Explanation:
I’m not 100% sure but I’m thinking B or C
Glucose molecules that are linked by alpha-1,4 glycosidic linkages have a curve at the bond as compared to a beta-1,4 glycosidic linkages which are straight because of the nature of the bonds. The linear beta linkage is due to how the molecules are placed in the chain which would cause the monosaccharide to have a rotation of 180 degrees which would be a straight bond.
The molecular formula of the compound is C12H15O3 hence the molar mass of the compound is 207 g/mol.
We need to obtain the number of moles of carbon, hydrogen and oxygen in the compound;
Carbon = 24.91 g/44g/mol × 1 mole of carbon = 0.566 moles
Mass of carbon = 0.566 moles × 12 g/mol = 6.792 g
Number of moles of hydrogen = 6.522 g/18 g/mol × 2 moles = 0.725 moles
Mass of hydrogen = 0.725 moles × 1 g/mol = 0.725 g
Mass of oxygen = 10 - (6.792 g + 0.725 g) = 2.483 g
Number of moles of oxygen = 2.483 g/16 g/mol = 0.155 moles
Now we must divide through by the lowest number of moles;
C - 0.566/0.155 H - 0.725/0.155 O - 0.155/0.155
C - 4 H - 5 O - 1
The simplest formula is C4H5O Recall that the molar mass of the compound lies between 150.0 and 220.0 g/mol
4(12) + 5(1) + 16 = 69
Hence; n = 3 and the molecular formula of the compound is C12H15O3
The molar mass of the compound is; 12(12) + 15(1) + 3(16) = 207 g/mol
Learn more: brainly.com/question/15180604
Molar mass of iron(III) oxide is 160g/mol
160g ----------- of iron(III) oxide is ---------------- 6.02*10²³molecules
79g ----------- of iron(III) oxide is ---------------- x
x = [6.02*10²³*79g]/160g ≈ <span>2.97*10²³ molecules</span>