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Dimas [21]
1 year ago
6

the ground-state valence-shell configuration of a particular atom is 4d105s25p1. the element to which this atom belongs is a

Chemistry
1 answer:
just olya [345]1 year ago
6 0

The element to which this atom belongs is a p-block main-group element.

What is general electronic configuration?

Electronic configuration or general electron configuration or electronic structure of atoms or ions is the arrangement of orbital energy levels for s, p, d, and f-block elements of the periodic table.

Which group are p-block elements in the periodic table write the general electronic configuration of a p-block element?

Groups 13, 14, 15, 16, and 17 elements comprise the p-block elements. The general configuration of p-block elements is ns2np(1−6).

What is the general configuration of p- block elments?

The general electronic configuration of p-block elements is ns2np1-6 (Except Helium). The number of electrons in the p-block element's penultimate shell is either 2 or 8 or 18.

Therefore, the element belongs to the p-block.

To know more about p-block elements:

brainly.com/question/20425962

#SPJ4

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How does removing thermal energy from liquid water affect the molecules in the water?
galina1969 [7]

Answer:

For deposition to happen, thermal energy must be removed from the gas. ... As water vapor loses thermal energy, it changes into solid frost. States of Water. Water is the only substance that exists naturally as a solid, a liquid, and a gas within Earth's temperature range.

Explanation:

3 0
2 years ago
How can you use the periodic table to find the number of protons in one atom of an element?
evablogger [386]
A is your answer.
On the periodic table the atomic number is the number of protons inside the nucleus.
6 0
3 years ago
Read 2 more answers
What is the mass percent of water in copper (II) sulfate?
Veseljchak [2.6K]
The answer is sulfate pentahydrate 


  Hope this helps you :D
8 0
3 years ago
Mass=1.01 kg; volume =1000cm3
guajiro [1.7K]

Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3

Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3

= 1010 kg/m^3


7 0
3 years ago
Linda performed the following trials in an experiment. Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0
nexus9112 [7]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

To calculate the amount of heat absorbed or released, we use the following equation:

q=mc\Delta T    .....(1)

where, q = amount of heat absorbed or released.

m = mass of the substance

c = heat capacity of  water = 4.186 J/g ° C      

\Delta T = Change in temperature

  • <u>For Trial 1:</u>

We are given:

m=30g\\\Delta T=[40-0]^oC=40^oC\\q=?J

Putting values in equation 1, we get:

q=30g\times 4.186J/g^oC\times 40^oC

q = 5023.2 J

  • <u>For trial 2:</u>

We are given:

m=40g\\\Delta T=[40-30]^oC=10^oC\\q=?J

Putting values in equation 1, we get:

q=40g\times 4.186J/g^oC\times 10^oC

q = 1674.4 J

Heat gained by Trial 1 than trial 2 = (5023.2-1674.4)J=3347J

Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.

Thus, the correct answer is Option b.

4 0
3 years ago
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