Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Let's break apart 42.
The 4 is in the tens. The 2 is in the ones.
Place Value starting from Thousands
Thousands Hundreds Tens Ones
_________ ________ ____ _____
4 2
So this is how we break up numbers using place value.
Hope this helps!
Answer:
y = -2x + 2 i think
Step-by-step explanation:
Answer:
1800
Step-by-step explanation:
there are 60 seconds in a minute
so, 30 * 60 = 1800