Answer: A=1, B=3, C=12
Explanation:
For this problem, you will need to know your unit conversions. There are 3 ft in 1 yard. Knowing this, we can find A, B, C.
For A and B, we know that we want to cancel out ft so the answer can be in yards. To do so, we need to put B=3 and A=1.
Now that we know the unit conversion, we can directly solve.
36 ft×(1 yd/3 ft)=12 yd
Our final answer is A=1, B=3, C=12.
Answer:
4) 0.5507 Mol Ar
5) 44.548 Mol AgNO3
6) 2.16107 Mol Li
Explanation:
Divide = grams to mol and mol to molecules
Multiply = molecules to mol and mol to grams.
3) 22 <em>g of Ar</em> 1 mol 22
-------------------- * ---------------------- = ------------ (turn to decimal) = 0.5507 Mol Ar
39.948 <em>g of Ar</em> 39.948
4) AgNO3 = (Ag; 39.948) (N; 14.007) (O^3; 48)
39.948 + 14.007 + 48 = 101.955
7.4 x 10^23 Mc 6.02 x 10^23 Mc
---------------------- * ------------------------- = 44.548 Mol AgNO3
1 mol
5)
15g 1 Mol 15
------- * ------------------- = --------- (turn to decimal) = 2.16107 Mol Li
6.941 g of Li 6.941
Answer:
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Answer:
A) 3.17 g of Zn
Explanation:
Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.
Zn⁺²(aq) + 2e⁻ → Zn(s)
We can establish the following relations:
- 1 min = 60 s
- 1 A = 1 C/s
- The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
- When 2 moles of electrons circulate, 1 mole of Zn is deposited.
- The molar mass of Zn is 65.38 g/mol
The mass of Zn deposited under these conditions is:
