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3 years ago

Is filling up beakers with 200ml of water bad

Chemistry

1 answer:

iogann1982 [59]3 years ago

6 0

Answer:

Explanation:

Filling a beaker 200ml of water is not bad because Each beaker's capacity may vary according to the size of different beaker.

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If it take 20 second for 200cm3 of H25 to diffuse through a porovs pot,hours,long will it take 400cm3 of NH3 of diffuse under th

trapecia [35]

Answer:

40 seconds chief just double it

Explanation:

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2 years ago

A weak bond called a ______ bond results from an attraction between a slightly positive region in a molecule and a slightly nega

tamaranim1 [39]

Answer: The weak bond having slightly positive region and a slightly negative region is polar covalent bond.

Explanation:

Covalent bond is defined as the bond which is formed by the sharing of electrons between the atoms. For Example: HCl, $CH_4$ etc..

They are of two types:

Polar covalent bond: This bond is formed when difference in electronegativity between the atoms is present. When atoms of different elements combine, it results in the formation of polar covalent bond.

In this bond, a dipole is created. More electropnegative atom will have a slight negative charge and less electronegative atom will have a slight positive charge. For Example: $CO_2,NO_2$ etc..

Non-polar covalent bond: This bond is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. For Example: $N_2,O_2$ etc..

Hence, the weak bond having slightly positive region and a slightly negative region is polar covalent bond.

7 0

2 years ago

را

Aloiza [94]

Answer:

A.It is the same for every sample of a single substance.

Explanation:

7 0

2 years ago

A particle with a charge of 9.40 nC is in a uniform electric field directed to the left. Another force, in addition to the elect

juin [17]

Answer:

a. Work done by the electric force = -2.85 * ×10⁻⁵ J

b. The potential of the starting point with respect to the end point = -3.03 * 10³ V

c. The magnitude of the electric field is 33.7kV/m

Explanation:

Given.

Charge = Q = 9.40 nC

Distance = d = 9.00 cm = 0.09m

Amount of work = 7.10×10⁻⁵ J

Kinetic energy = K = 4.25×10⁻⁵ J

a. What work was done by the electric force?

This is calculated by; change in Kinetic Energy i.e. ∆KE

∆KE = ∆K2 - ∆Kæ

Where K2 = 4.25×10⁻⁵ J

The body is released at rest, so the initial velocity is 0.

So, K1 = 0

Also, total work done = W1 + W2

Where W2 = 7.10×10⁻⁵J

So, W1 + W2 = W = K2

W1 + 7.10×10⁻⁵ = 4.25×10⁻⁵

W1 = 4.25×10⁻⁵ - 7.10×10⁻⁵

W = -2.85 * ×10⁻⁵ J

Work done by the electric force = -2.85 * ×10⁻⁵ J

b. What is the potential of the starting point with respect to the end point?

The change in potential energy is given as

W = ∆U

W = Q|V2 - V1| where V1 = 0 because the body starts from rest

So, W = QV2

Make V the Subject of the formula

V2 = W/Q

V2 = -2.85 * ×10⁻⁵ J / 9.40 nC

V2 = -2.85 * ×10⁻⁵ J / 9.40 * 10^-9C

V2 = −3031.9148936170212765957V

V2 = -3.03 * 10³ V

The potential of the starting point with respect to the end point = -3.03 * 10³ V

c. What is the magnitude of the electric field?

The magnitude of the electric field is calculated as follows;

W = -Fd = -QEd

And E = V/d

E = -3.03 * 10³ V / 0.09 m

E = −33687.943262411347517730 V/m

E = -33.7kV/m

The magnitude of the electric field is 33.7kV/m

4 0

2 years ago

Which order system shows the levels of organization from largest to smallest

Yanka [14]

Answer:

the answer is organism tissue organ system organ cell

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3 years ago