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quester [9]
3 years ago
9

What mass, in grams, of NaNo, is needed to make 6.24 Liters of a 0.500 M solution?

Chemistry
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

that hared ldkdjjjdjjdjdjj

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Marrrta [24]

Answer:

chemical

Explanation:

5 0
3 years ago
Plss answer the question in the picture. If you actually answer I will give you brainilest!!!
DedPeter [7]

Answer:

hey :)

your answer is D.

Explanation:

To find density, you must divide mass and volume.

8 divided by 4 is 2

6 divided by 6 is 0

4 divided by 2 is 2

hope i helped any :))

6 0
3 years ago
How are catapults an example of a third class lever? Please explain!
Katen [24]
I hope that you can understand this!!! Lol

The thing that you have to pull back to release with, that would be considered a third class lever.

I hope this helps. :)
3 0
3 years ago
7.The _____ theory of matter states that all particles of matter are in constant motion.
SashulF [63]
The kinetic energy theory of matter states that all particles of matter are in constant motion.
Kinetics has to do with some kind of movement, which is why this answer is the only plausible one. 
6 0
3 years ago
Read 2 more answers
Write the complete balanced equation for the neutralization reaction that occurs when aqueous hydroiodic acid, HI, and sodium hy
Serhud [2]

Answer:

H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g )

Explanation:

The complete reaction when hydroiodic acid and sodium hydrogen carbonate combine, would be as follows -

HI + NaHCO3 ----> NaI + H2O + CO2

net reaction

H2CO3 is highly unstable, and thus decomposes into the water and carbon dioxide you see present as the reactants. If you didn't know already, H2CO3 is also reffered to as carbonic acid. The rest of the elements present on the reactant side are Iodine and Sodium, which is why they are present on the product side as NaI.

Let me include the " physical states " in this reaction as well -

HI ( aq ) + NaHCO3 ( aq ) ----> NaI ( aq ) + H2O ( l ) + CO2 ( g )

Now the complete ionic equation would simply be each compound present as ions in an aqueous solution, so there is no need for an explanation on this step -

H+ ( aq ) + I- ( aq ) + Na+ ( aq ) + HCO3- ( aq ) -------> Na+ ( aq ) + I- ( aq ) + H2O( l ) + CO2 ( g )

The spectator ions in this reaction are I- and Na+, so canceling them out, you would receive the following net ionic equation -

H+ ( aq ) + HCO3- ( aq ) ------> H2O( l ) + CO2 ( g )

<u><em>Hope that helps!</em></u>

4 0
3 years ago
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